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# 1  
Old 11-09-2010
help with awk

hi i have multiple rows of several outputs.
Code:
find: ./filename: Permission denied

i want to suppress the rows which say permission denied.

i was thinking of using awk for this
Code:
command | awk '( $3 != Permission denied) '

and it doesn't work. my skills are just novice level in sed, awk and any help would be really helpful. thanks.

---------- Post updated at 12:39 PM ---------- Previous update was at 12:33 PM ----------

my output sorta looks like this,
Code:
find: ./hmwk8: Permission denied
./.bashrc.sample

so i don't know what field Permission denied is in 2nd or 3rd but still does not work.

Last edited by Scott; 11-09-2010 at 05:43 PM.. Reason: Please use code tags
# 2  
Old 11-09-2010
No need to use awk or sed, you can redirect the errors to /dev/null:
Code:
command 2>/dev/null

This User Gave Thanks to Franklin52 For This Post:
# 3  
Old 11-09-2010
i tried
Code:
find -mtime -30 -print > /dev/null

now it only prints out lines containing Permission denied, opposite of what i wanted. thanks for reply.
# 4  
Old 11-09-2010
Should be:
Code:
find -mtime -30 -print 2> /dev/null

This User Gave Thanks to Franklin52 For This Post:
# 5  
Old 11-09-2010
thank you very much for quick reply and follow up.
works perfect.
# 6  
Old 11-09-2010
The reason this works is because the normal output and error messages are printed to two different files, standard output(FD 1) and standard error(FD 2). In a shell they'd both go to the same place, the screen, but you can still redirect them separately.
 

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