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appending running numbers on a variable

 
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# 1  
Old 10-22-2010
appending running numbers on a variable
hi guys,

would appreciate some help here. I need to append running numbers using sed onto a variable that contain a list of IP addresses. I'm basically stuck on the running number part. e.g.

1. 10.0.0.1
2. 10.0.0.2
3. 10.0.0.3
# 2  
Old 10-22-2010
please give more input what did you try so far ?
what do you mean by "running"?
# 3  
Old 10-22-2010
Quote:
Originally Posted by ctsgnb
please give more input what did you try so far ?
what do you mean by "running"?
i meant ascending numbering

e.g.

input:

Code:
10.0.0.1
10.0.0.2
10.0.0.3

output:
Code:
1. 10.0.0.1
2. 10.0.0.2
3. 10.0.0.3

Last edited by vgersh99; 10-22-2010 at 11:26 AM.. Reason: code tags, please!
# 4  
Old 10-22-2010
Quote:
sed = input | sed 'N;s/\n/. /'
# 5  
Old 10-22-2010
Code:
sed '=' input | sed 'N;s/\n/ /' > output

# 6  
Old 10-22-2010
Code:
cat -b input > output

or
Code:
cat -n input > output

or in ksh (don't know whether bash has the same $LINENO built in variable
Code:
( { while read line ; do echo "$LINENO. $a" ; done } <input ) >output

# 7  
Old 10-22-2010
Quote:
Originally Posted by vgersh99
Code:
sed '=' input | sed 'N;s/\n/ /' > output

Code:
`printf "$VAR" | sed 'N;s/\n/. /'`

sorry, can't seem to get it to work



---------- Post updated at 10:14 AM ---------- Previous update was at 09:56 AM ----------




Quote:
Originally Posted by ctsgnb
Code:
cat -b input > output

or
Code:
cat -n input > output

or in ksh (don't know whether bash has the same $LINENO built in variable
Code:
( { while read line ; do echo "$LINENO. $a" ; done } <input ) >output

it's odd I can't do cat in my script

Code:
cat -n "$VAR"

Code:
error:
cat: cannot open

 
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