UNIX for Dummies Questions & Answers

Hello all,

i have tons of files in folder named like this (yyyymmdd):

bookcollection20100729
bookcollection20100730
bookcollection20100731
bookcollection20100801
bookcollection20100802

etc.

I need to find files with date range in there names lets say from 2010.07.30 - 2010.08.02

I tried with grep

grep -h --mmap 'horror' /usr/local/data/books/bookcollection201007[10-11]*

But it doesn't work, i can change just date, and not year and months.

The plan is that I will have a script that will ask from user date range input as 2010.07.30 - 2010.08.02 then I will add those years, months and days to variables that I can append to grep/sed command and display result

But I m stuck. Any ideas?

Code:

ls bookcollection* |awk -v start=20100730 -v end=20100802 '{d=substr($0,15); if (d>=start&&d<=end) print}'

or

Code:

D1="20100730"
D2="20100802"

ls bookcollection* |awk -v start=$D1 -v end=$D2 '{d=substr($0,15); if (d>=start&&d<=end) print}'

This doesn't work, I forgot to mention that there si time append so filenames are bookcollection20100728_001500.

Time doesn't matter to me, just yy, mm and dd. Any new suggestion or reformulation?

Thanks in advance

Regards

==========EDIT
Tx a alot it works, I new at awk so I needed more time to figure it out

Oke, this works great but how to include the "start" and "end" variables into results. Because when i enter range for today 2010.08.29 - 2010.08.29, it display nothing.

Now, it displays this for rage 2010.07.30 - 2010.08.02:
bookcollection20100731
bookcollection20100801

But I need that awk displays this:
bookcollection20100730
bookcollection20100731
bookcollection20100801
bookcollection20100802

Tx,

Regars

Do you mean something like this?

Code:

D1="20100730"
D2="20100802"
grep -h 'horror' $( ls -d bookcollection* | sed -n "/$D1/,/$D2/p" )

This is assuming that your ls sorts alphabetically, otherwise you could perhaps use:

Code:

grep -h 'horror' $( ls -d bookcollection* | sort | sed -n "/$D1/,/$D2/p" )

Code:

ls bookcollection* |awk -F \_ -v start=20100730 -v end=20100802 '{d=substr($1,15); if (d>=start&&d<=end) print}'

Ty people, this works great

---------- Post updated at 08:42 AM ---------- Previous update was at 03:05 AM ----------

SED version works but it is slow because of | sort|, so I prefer AWK, and this code above works great except it doesn't display last day =20100802 it stops on 20100801, also when I choose for example start=20100808
and end=20100808 it display nothing???

I tried modifying code buy my AWK skills are terrible:/, any help?