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Searching the date pattern in a file


 
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# 1  
Searching the date pattern in a file

Hi,

I would like to search the pattern based on the date like "2010/08/15". I tried using / in the file giving /<<pattern>>. when i tried this it turns to /2010/+8, but not going to the pattern what ever i want.

This is how the data in the file.

Code:
INFO   | jvm 1    | 2010/05/26 13:30:33 | processing file:body.xsl (null)...

Please advice.

Many thanks.
# 2  
If this is not what you're looking for, elaborate your question:
Code:
grep '2010/05/26' file

# 3  
I would like to search the pattern in the file itself, not from the command prompt.

After opening the file ( vi filename ), we can check it with "/<<pattern>>" in vi, i want to know how to search the date pattern like this.
# 4  
In vi that would be "/20[0-9][0-9]\/[0-9][0-9]\/[0-9][0-9]"
# 5  
Simple.. /2010\/05\/26
# 6  
thanks a lot guys mubeen and konsolebox.
 

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