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Basic if statement problem

 
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# 1  
Old 07-19-2010
Basic if statement problem
I am using the following code:
Code:
if [ $FILE = IMG* ]; then

I am getting an error saying
Code:
line 12: [: too many arguments

The code is supposed to examine whether the filename read into $FILE includes the string IMG*. I do have a fi later in the script, but I must be missing something obvious. Can anyone help?
# 2  
Old 07-19-2010
IMG* is a wild card resulting more than 1 value. Try the following.

Quote:
#!/bin/sh

# Get the files:
FILES=`ls -1`

for FILENAME in $FILES
do
if [substr($FILENAME, 0, 3) = 'IMG' ]; then
---
---
--
done
# 3  
Old 07-20-2010
Quote:
Originally Posted by Bengel
Code:
if [ $FILE = IMG* ]

Code:
if [[ $FILE =~ IMG ]] # filename contains 'IMG', e.g. 'someIMGfile'
if [[ $FILE =~ ^IMG ]] # filename starts with 'IMG', e.g. 'IMGfile'

This User Gave Thanks to dr.house For This Post:
rdcwayx
# 4  
Old 07-20-2010
Thanks Dr. House - that works like a charm!
 
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