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ls to show numeric permission bit ...

 
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# 1  
Old 07-19-2010
ls to show numeric permission bit ...
Hi all,

Is there an option in ls that will show the permission bit in numbers instead of the permissions?

The ls output below are very useful I guess, but I want to know if it is possible to run ls where it just shows 600 I guess which is the numeric equivalent of the permission bit of the file. Basically, am looking for something similar to the Linux's stat -c "%a %n" testfile. Unfortunately, stat is not available in Solaris.

BTW, the output from ls -v, why does the group has #effective label, what does that mean? Can't understand what the output from ls -v means, I've already check on the man pages and still don't understand it, anyone who can give a better explanation about what the output from ls -v means, mainly on the line 2:mask:rwx, the other lines, I can "guess" what they means ... Smilie

Thanks in advance.

Code:
$ ls -v testfile
-rw-------   1 root     root           0 Jul 19 13:31 testfile
     0:user::rw-
     1:group::---               #effective:---
     2:mask:rwx
     3:other:---
$ ls -e testfile
-rw-------   1 root     root           0 Jul 19 13:31:36 2010 testfile
$ ls -l testfile
-rw-------   1 root     root           0 Jul 19 13:31 testfile

Last edited by newbie_01; 07-19-2010 at 02:43 AM.. Reason: More information
# 2  
Old 07-19-2010
AFAIK, ls cannot show numeric permission bits.

But, you can write a simple script which can read and convert this rwx to appropriate numeric bits and make it to show to you.
# 3  
Old 07-19-2010
You can use Perl:

Code:
perl -le'
  printf "%s is mode %o\n", $_, 07777 & (stat)[2] 
    for @ARGV
    ' *

As far as the ACLs are concerned:

Quote:
The user and group permissions are those for the owner (user) and the default group (prof), respectively. The mask indicates the maximum permission available to all users, except the owner. The effective permission, to the right of the group permission, represents the intersection (bitwise AND) of the specified permissions for a user/group and the mask field. The effective permission is what a user, other than the owner, will see when they try to access the file
The quote is from this url.
Last edited by radoulov; 07-19-2010 at 04:55 AM..
# 4  
Old 07-19-2010
Code:
#!/bin/bash

ls -lhF $1 | while read DATA
do
  case "${DATA:0:1}" in
  "-"|"d")
    PERM=$( echo "${DATA:1:9}" | sed 's/-/0/g;s/r/4/g;s/w/2/g;s/x/1/g' )
    P_US=$((${PERM:0:1}+${PERM:1:1}+${PERM:2:1}))
    P_GR=$((${PERM:3:1}+${PERM:4:1}+${PERM:5:1}))
    P_OT=$((${PERM:6:1}+${PERM:7:1}+${PERM:8:1}))
    DATA=$( echo "$DATA" | sed "s/${DATA:0:10}/${P_US}${P_GR}${P_OT}/" )
    echo "$DATA"
  ;;
  *)
    continue
  ;;
  esac
done

exit 0
#finis

Code:
[house@leonov] ll .
total 8.0K
-rw-r--r-- 1 house house 450 19. Jul 11:32 code
[house@leonov] bash code .
644 1 house house 450 19. Jul 11:32 code
[house@leonov] ll ..
total 798K
-rw-r--r--  1 house house 534K 14. Jul 10:31 bootchart_long.jpg
-rw-r--r--  1 house house 219K 14. Jul 10:31 bootchart_short.jpg
-rwxr-xr-x  1 house house 4.3K 14. Mai 17:28 chromify
drwxr-xr-x 16 house house  648 18. Jul 11:45 Labour/
drwxr-xr-x  2 house house  208  1. Mai 17:04 Mahab/
drwxr-xr-x  8 house house  368 12. Mai 12:00 Scratch/
[house@leonov] bash code ..
644  1 house house 534K 14. Jul 10:31 bootchart_long.jpg
644  1 house house 219K 14. Jul 10:31 bootchart_short.jpg
755  1 house house 4.3K 14. Mai 17:28 chromify*
755 16 house house  648 18. Jul 11:45 Labour/
755  2 house house  208  1. Mai 17:04 Mahab/
755  8 house house  368 12. Mai 12:00 Scratch/

# 5  
Old 07-20-2010
Quote:
Originally Posted by radoulov
You can use Perl:

Code:
perl -le'
  printf "%s is mode %o\n", $_, 07777 & (stat)[2] 
    for @ARGV
    ' *

But, why I am getting result 420 for the below command?
Code:
perl -le 'print (07777 & (stat("./file.txt"))[2])'

The expected answer is 644
# 6  
Old 07-20-2010
Quote:
Originally Posted by royalibrahim
But, why I am getting result 420 for the below command?
Code:
perl -le 'print (07777 & (stat("./file.txt"))[2])'

The expected answer is 644
Hi.

You're displaying the result in decimal. It should be in octal (%o)

Code:
$ printf "%o\n" 420
644

Last edited by Scott; 07-20-2010 at 02:35 AM..
This User Gave Thanks to Scott For This Post:
radoulov
 
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