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Unix Command to separate this years files and last years?

 
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# 1  
Old 06-21-2010
Unix Command to separate this years files and last years?
Hello - I have a folder that contains files from 2003 till 2010. I am trying to figure out a command that would seperate each years file and show me a count?

Even if i can find a command that would give me year by year count, thats good enough too.

Thanks
# 2  
Old 06-21-2010
Question Need more info
Can you supply an example of the files? That will make it possible to provide a command, or set of commands, to accommodate your request?
Are you looking to separate by filename, or by last edit (or other) date?
# 3  
Old 06-21-2010
I am trying to figure out how many files were created each year. And if possible, break down by each month of that year.

The file formats are different. Such as these:

Systemerror-1-8-2010 7_00_06 PM.xml (PM remains constant)

2004-01-08.txt

DATE2007-02-12.txt
# 4  
Old 06-21-2010
Hi,

you can use something as :

Code:
#ls -lrth|awk '$8 == 2003 {print}'|wc -l

then change 2003 with 2004,2005,2006... etc.

Smilie
This User Gave Thanks to Reboot For This Post:
DallasT
# 5  
Old 06-21-2010
This is good.. till i put 2010 and it shows 0. Although i have 2010 files..

And is there a way for me to break month by month..
# 6  
Old 06-21-2010
Files less than 6 months old show the time of day instead of the year.
# 7  
Old 06-21-2010
No time to post an example. The technique is to create reference files with "touch" with specific timestamps (e.g 31 Dec 2009 23:59) then use "find -newer reference_file_name". By building "and not" conditions in "find" it is possible to define year ranges or any other timespan.
 
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