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how to get start time of a running process

 
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# 1  
Old 06-01-2010
how to get start time of a running process
I am trying to see if a process is running what was its start time.

here is the code that I am using

Code:
if [ `ps -elf | grep batch_output_x | grep -cv grep` = 0 ]
then
    echo 'Gateway output processing started.' 
else       
 VAR=$(ps -ef | grep batch_output_x )
...

fi

now the problem i see is when the process is running i get two lines like this

Code:
splgwdv 29898 29893  0 11:01:20 pts/ta    0:00 grep batch_output_x
splgwdv 29827 18757  0 11:01:08 pts/tb    0:00 /usr/bin/ksh ./batch_output_x.sh

I need to get the second line time (11:01:08) as the first line is the current time.

Why is that line giving me two results
and how do I get the second line?
because when I am doing this

Code:
        VAR=$(ps -ef | grep batch_output_x )

        FTP_HOUR=$(echo $VAR|cut -c23-24)
        FTP_MIN=$(echo $VAR|cut -c26-27)
        FTP_SEC=$(echo $VAR|cut -c29-30)

        echo "Time: $FTP_HOUR:$FTP_MIN:$FTP_SEC"

its returning Time: 11:01:20
# 2  
Old 06-01-2010
Code:
if [ `ps -elf | grep batch_output_x | grep -cv grep` = 0 ]
then
    echo 'Gateway output processing started.' 
else       
 VAR=$(ps -ef | grep batch_output_x )...

fi


You are not excluding the grep process . Thats why you are getting two lines.
So change as per bellow code

Code:
VAR=$(ps -ef | grep batch_output_x | grep -v grep)



Also
Code:
 VAR=$(ps -ef | grep batch_output_x )

        FTP_HOUR=$(echo $VAR|cut -c23-24)
        FTP_MIN=$(echo $VAR|cut -c26-27)
        FTP_SEC=$(echo $VAR|cut -c29-30)

        echo "Time: $FTP_HOUR:$FTP_MIN:$FTP_SEC"

The process id might change as it can be of any length. So use awk instead of cut.
Code:
time=`echo $VAR | awk { print $5 }`
echo $time

Last edited by amitranjansahu; 06-01-2010 at 01:34 PM..
This User Gave Thanks to amitranjansahu For This Post:
akabir77
# 3  
Old 06-01-2010
Quote:
Originally Posted by amitranjansahu
Code:
if [ `ps -elf | grep batch_output_x | grep -cv grep` = 0 ]
then
    echo 'Gateway output processing started.' 
else       
 VAR=$(ps -ef | grep batch_output_x )...

fi

You are not excluding the grep process . Thats why you are getting two lines.
So change as per bellow code

Code:
VAR=$(ps -ef | grep batch_output_x | grep -v grep)

how can I check if the VAR is empty or not? I found out that if the process is not running it returns blank or empty.
# 4  
Old 06-01-2010
check this .
https://www.unix.com/shell-programmin...-variable.html
This User Gave Thanks to amitranjansahu For This Post:
akabir77
 
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