need help with awk


 
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# 1  
Old 05-28-2010
need help with awk

I have set variables and then exported
export xxx_DB etc
But I do not see why in my script this does not wrk, can sonehelp

Code:
pass=`awk -F: '$xxx_DB ~ /'$ORACLE_SID'/ {print $xxxx_ID}' $pwfile`


Last edited by vgersh99; 05-28-2010 at 12:27 PM.. Reason: code tags, PLEASE!
# 2  
Old 05-28-2010
variable expansion does not happen inside ' '.
Code:
pass=`awk -F: -v xxx_DB=$xxxDB -v xxxx_ID=$xxxx_ID 'xxx_DB ~ /'$ORACLE_SID'/ {print xxxx_ID}' $pwfile`

Solaris try nawk, not awk.
If you have an older version of awk consult the man page on passing variables from the command line (the -v bit)
This User Gave Thanks to jim mcnamara For This Post:
# 3  
Old 07-20-2010
Variable not holding it's value in awk statement

Thanks for the post.... I have been trying to figure out
why my variable doesnt have a value in my awk statement


This doesnt work:
Code:
cat <file> | awk '{ if ( $1 == $variable ) print $0 }'

This works:
Code:
cat <file> | awk -v variable=$variable '{ if ( $1 == variable ) print $0)'

THANKS!

Last edited by Scott; 07-20-2010 at 05:20 PM.. Reason: Code tags, please...
# 4  
Old 07-20-2010
Quote:
Originally Posted by shunter0810
Thanks for the post.... I have been trying to figure out
why my variable doesnt have a value in my awk statement


This doesnt work:
Code:
cat <file> | awk '{ if ( $1 == $variable ) print $0 }'

This works:
Code:
cat <file> | awk -v variable=$variable '{ if ( $1 == variable ) print $0)'

THANKS!
Just for reference...

Code:
awk -v variable="$variable" '$1 == variable' <file>

is the same thing (you don't need cat)
 
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