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# 1  
Old 05-26-2010
copy files
Hi Team,

I am unable to copy the files, when i run the below script, i am getting error as file not present, not sure what i am missing.

Code:
# File to be looked upon

File_Pattern='*.zip'
TMP_FILE=flagfile


Check[1]=`find  $Directorypath -name $File_Pattern -type f  -newer $TMP_FILE -print | sed "s;.*/;;"

if [${Check[1]}]
then `cp  $FROM_Directorypath${Check[1]} $TO_Directorypath${Check[1]}` --------these files are not getting copied... 
fi

Last edited by Scott; 05-26-2010 at 12:39 PM.. Reason: Code tags, please...
# 2  
Old 05-26-2010
Try this :

Code:
# File to be looked upon

File_Pattern='*.zip'
TMP_FILE=flagfile


Check[1]=`find $Directorypath -name $File_Pattern -type f -newer $TMP_FILE -print | sed "s;.*/;;"

if [${Check[1]}]
then 
cp $FROM_Directorypath${Check[1]} $TO_Directorypath${Check[1]}
fi

Smilie
# 3  
Old 05-26-2010
You may need to use a backslash "\" in front of the asterisk "*" in your $File_Pattern var.
# 4  
Old 05-26-2010
Quote:
Originally Posted by Naveen_5960
Hi Team,

I am unable to copy the files, when i run the below script, i am getting error as file not present, not sure what i am missing.

Code:
# File to be looked upon
 
File_Pattern='*.zip'
TMP_FILE=flagfile
 
 
Check[1]=`find  $Directorypath -name $File_Pattern -type f  -newer $TMP_FILE -print | sed "s;.*/;;"
 
if [${Check[1]}]
then `cp  $FROM_Directorypath${Check[1]} $TO_Directorypath${Check[1]}` --------these files are not getting copied... 
fi



USE Following :

Code:
#!/usr/bin/bash

File_Pattern=\*.zip
TMP_FILE=flagfile


Check[1]=`find $Directorypath -name "$File_Pattern" -type f -newer $TMP_FILE -print | sed 's;.*/;;'
if [${Check[1]}]
then 
cp $FROM_Directorypath${Check[1]} $TO_Directorypath${Check[1]}
fi

Smilie
# 5  
Old 05-26-2010
Quote:
Originally Posted by Naveen_5960
Check[1]=`find $Directorypath -name $File_Pattern -type f -newer $TMP_FILE -print | sed "s;.*/;;"`
Here I see respectively don't see a "closing" backtick...

Question: Why do you "kill" the absolute path with sed? That might also be a failing point, because there might be files, which are found in a subdirectory of $Directorypath, hence these cannot be copied.
# 6  
Old 05-26-2010
Tried with \*.zip,

Code:
if [${Check[1]}]
then
cp  $viewing${Check[1]} $TEMP${Check[1]}
fi

and even the abs path too(without killing), even that did not work. Any other ideas Guys.

Moderator's Comments:
Mod Comment Please use code tags
Last edited by Scott; 05-26-2010 at 06:25 PM..
# 7  
Old 05-26-2010
All right, now I know why you used the sed command Smilie

1. Did you fix the missing backtick?
2. Can you try this (from terminal / command line):
Code:
File_Pattern=\*.zip
TMP_FILE=flagfile
Check=`find $Directorypath -name "$File_Pattern" -type f -newer $TMP_FILE -print | sed 's;.*/;;'`
if [ $Check ]
then
cp $viewing$Check $TEMP
fi

3. If the above won't work, why not simply try this:
Code:
File_Pattern=\*.zip
TMP_FILE=flagfile
find $Directorypath -name "$File_Pattern" -type f -newer $TMP_FILE -exec cp {} /new/directory \;

4. If none of the above won't work, please post your whole script, tell us your current working directory (pwd) and the destination directory.
 
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