UNIX for Dummies Questions & Answers

Ok, I searched the threads a couple of times but couldn't find anything really relevant. Here's my problem, maybe you can help:

I am running version 1.14.7 of the bash shell, on Red Hat Linux. I am trying to set an array like so:

bash$> letters=(x y z)

spaces are between the letters but not between the parenthesis and the equals

Now, on version 2.01.1 running on a Sun machine that command works fine, the array set properly, but for some reason it won't take on the older version. This must mean that i'm doing it wrong and the old version has a different way to set arrays. If someone knows the answer as to whether or not you can do this on the old version and how it's done, i would really appreciate it.

The catches are that the one system is not mine and I don't have the authority to upgrade the bash shell to the newer version, and the scripts I wish to create and run must be run on the system with the old bash shell. I've also checked the bash manual for this old version and didn't really find anything of use. Maybe I missed something, please help if you can. Thanks.

K

Have you tried explicitly seeting the values:

letters[0]="x"
letters[1]="y"
letters[2]="z"

Yes, i tried setting it explicitly but it won't take it. It gives me back the line:
letter[0]=x: command not found

I've tried doing it other ways also (w/ and w/out quotes, setting the variable to a single letter first i.e. letter=x then setting the next index
letter[1]=x) Just different things to that effect and i haven't found one that works yet.

Any more suggestions would be greatly appreciated.

I would consider upgrading to the newer version then:

http://www.rpmfind.net/linux/RPM/red...4-11.i386.html