UNIX for Dummies Questions & Answers

when ever i type it in it always looks like so

Code:

echo $file | sed 's/~/\
/g'

how can i get it on one line?

... ^j is a hard return
try escaping the carrot and the j
ie: '\^\j'
why the need for it? is it some sortof global replace?
hope that helps

nope didnt work.

the purpose is a client send us a file ~ denotes a carrage return in this file. It then gets emailed to another computer as the body of a mesage (sometimes this file is well over the limit for the mail program and gets mutated in the transfer) so if i replace the ~ w/ carage returns we never have this problem. BUT it has to be on one line in my preferance.

well, the only other thing i can think of without actually working on it myself is to either try substituting the '^J' with a '^M' (escaping it of course - '\^\M') OR... and this may be a long shot - try double escaping it - '\\^\\J' or '\\^\\M' - that MIGHT work... (reason being is if you are calling it from a call....hence the double escaping)

Also you may be able to replace the ^J with the octal code of \015 (which is actually the same as a ^M)

I had the same issue as this a year or so ago and the octal code worked where the ^J did not, but then again there may be issues with using the ^J (linefeed) vs ^M (carriage returm)

answer:

Code:

tr '~' '\12'

man tr

What about using ctrl-v ctrl-j ? This works under bash in Linux, and ksh on HP-UX for sure. Ctrl-v makes the next character literal, not interpreted as the control-command.