print previous month (current month minus 1) with Solaris date and ksh


 
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# 1  
print previous month (current month minus 1) with Solaris date and ksh

Hi folks

Code:
month=`date +%m`

gives current month

Howto print previous month (current month minus 1) with Solaris date and ksh
# 2  
one way using shell only
Code:
#!/bin/ksh
last_month()
{
  set -A mon filler Dec Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov
  typeset -i var=$(date +%m)
  echo ${mon[var]}
}

last_month

If you want a numeric month
Code:
typeset -i var=$(( date +%m -1 ))
[[ $var -eq 0 ]]  && echo 12 || echo $var

# 3  
Quote:
Originally Posted by jim mcnamara
[/code]If you want a numeric month
[code]
typeset -i var=$(( date +%m -1 ))
[[ $var -eq 0 ]] && echo 12 || echo $var
Hi jim mcnamara

thanks for your answer. I wish numeric month, but it doesn't work:

Code:
$ ./test.sh
./test.sh[2]:  date +%m -1 : bad number

# 4  
Try this...

Code:
last_month=`date --date "last month" +%m`

# 5  
Quote:
Originally Posted by itkamaraj
Try this...

Code:
last_month=`date --date "last month" +%m`

SOLARISdate != GNUdate
# 6  
More or less based on jim_mcnamara's above, but allows for implicit and explicit usage:

Code:
last_month() 
{
   typeset my_arg="${1:-$(date '+%m')}" 
   typeset digit_array='01:12 02:01 03:02 04:03 05:04 06:05 07:06 08:07 09:08 10:09 11:10 12:11 ' 
   typeset alpha_array='Jan:Dec Feb:Jan Mar:Feb Apr:Mar May:Apr Jun:May Jul:Jun Aug:Jul Sep:Aug Oct:Sep Nov:Oct Dec:Nov ' 

   mon=$(echo ${digit_array} ${alpha_array} |tr ' ' "\n" |grep -n "^0*${my_arg}" |awk -F':' '{print $3;}')

   echo ${mon} 
}

last_month 
last_month 10 
last_month Apr

These 2 Users Gave Thanks to curleb For This Post:
# 7  
If your ksh is actually ksh93 ....
Code:
$ printf "%(%m)T\n" "last month"
04
$

 

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