sed insert command and variable expansion/command substitution


 
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# 1  
Old 03-08-2010
sed insert command and variable expansion/command substitution

I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename?

Code:
#!/bin/bash

filename=`echo $0`


/usr/bin/sed '/#include/ {
i\
the filename is `$filename`
}' $1
exit 0

# 2  
Old 03-08-2010
Code:
#!/bin/bash

filename=`echo $0`


/usr/bin/sed "/#include/ {
i\
the filename is `$filename`
}" $1
exit 0

# 3  
Old 03-08-2010
it doesnt work with double quotes
# 4  
Old 03-08-2010
Hi,

What is your requirement? If the file contains #include do you want to insert this line, the filename is "$filename" into the given file.
# 5  
Old 03-09-2010
Quote:
Originally Posted by glev2005
it doesnt work with double quotes
What do you mean by doesnt work?
# 6  
Old 03-09-2010
I want to insert the filename above the header directive information "#include" Using double quotes gives errors in the sed syntax specifically with the i\ (insert) command.

---------- Post updated at 11:49 AM ---------- Previous update was at 11:47 AM ----------

error is:

insert.sed: line 9: insert.sed: command not found
sed: 2: "/#include/ {\nithe filen ...": command i expects \ followed by text


insert.sed is my shell script.. it looks like
Code:
#!/bin/bash

filename=`echo $0`

 
/usr/bin/sed "/#include/ {
i\
the filename is `$filename`
} $1"
exit 0

# 7  
Old 03-09-2010
Add one more slash after command i
Code:
#!/bin/bash

filename=`echo $0`

 
/usr/bin/sed "/#include/ {
i\\
the filename is `$filename`
} $1"
exit 0

 
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