UNIX for Dummies Questions & Answers

Hi All,

I have a string in the following format
"abcd | fghfh | qwer | ertete"

I need to cut the values in the following format

line1 = abcd | fghfh | qwer
line2 = ertete

Simply speaking a want to cut all the values before the last delimiter from the line and print it on one line and the value after last delimiter on the other line.

For printing the second line i'm using " awk -F/ '{print $NF}' ", which prints the last word after the delimiter, but i'm stuck with my first requirement of printing all the other string before the last delimiter .

Can someone help me with this , thanks in advance.

Code:

$ str="abcd | fghfh | qwer | ertete"
$ echo $str
abcd | fghfh | qwer | ertete

$ echo ${str%|*}
abcd | fghfh | qwer

$ echo ${str##*|}
ertete

Its working, thanks alot If possible can u explain the logic as well, so i may use it in other generic cases.

Hi, this is called parameter expansion.

Thanks alot

My solution isn't so perfect

Code:

sh-3.1$ cat data

abcd | fghfh | qwer | ertete

sh-3.1$ cat data | awk -F"|" '{print "$1 "|" $2 "|" $3 "\n" $4}'

abcd | fghfh | qwer 

 ertete

Another solution using awk:

echo $str
abcd | fghfh | qwer | ertete
echo $str | awk -F'|' '{OFS="|";$NF="\n"$NF;print $0}'
abcd | fghfh | qwer |
ertete