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unix: extract a specific list of lines from a file

 
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# 1  
Old 11-24-2009
unix: extract a specific list of lines from a file
I would like to extract specific lines from a file and output them into another file.

Each line in the file has a unique ID, and I have a specific list of IDs (that are not consecutive) that I wish to extract.

for example:

Code:
1 aaaaaa bbbcb cccccc
2 aaaaaa bbbbb cccccd
3 aaaaaa bbbab cccccc
4 aaaaaa bbbxb cccccc
5 aaaaaa bbbbb cwcccc
6 aaaaaa bbbbb cqcccc

I wish to extract only lines 3 and 5 of this file, how do I do this?
Last edited by Scott; 02-23-2010 at 07:45 AM..
# 2  
Old 11-24-2009
If the list of id-s is not very very very long, it could be as follows:
Code:
cat file | egrep "id1|id2|id3|...|idk"

It must take some precautions if you could find the strings of identifiers elsewhere in the line. For example, if the ID is the beginning of the line, you can do like this:
Code:
cat file | egrep "^id1|^id2|^id3|...|^idk"

# 3  
Old 02-23-2010
MySQL
Using Sed: also we can achieve this requirement

Input file:

Code:
1 aaaaaa bbbcb cccccc
2 aaaaaa bbbbb cccccd
3 aaaaaa bbbab cccccc
4 aaaaaa bbbxb cccccc
5 aaaaaa bbbbb cwcccc
6 aaaaaa bbbbb cqcccc

Sample Code:
Code:
sed -n '/^[3|5]/p' input-file >output-file

Output file:
Code:
3 aaaaaa bbbab cccccc
5 aaaaaa bbbbb cwcccc

Last edited by ungalnanban; 02-23-2010 at 07:34 AM.. Reason: spell mistake correction
# 4  
Old 02-23-2010
Using grep command also you can achieve this.

consider that the data file is having the content as :

Code:
1 aaaaaa bbbcb cccccc
2 aaaaaa bbbbb cccccd
3 aaaaaa bbbab cccccc
4 aaaaaa bbbxb cccccc
5 aaaaaa bbbbb cwcccc
6 aaaaaa bbbbb cqcccc

grep 3  data > result_file && grep 5 data >> result_file

Now the result_file will contain the following contents

Code:
3 aaaaaa bbbab cccccc
5 aaaaaa bbbbb cwcccc

Last edited by Scott; 02-23-2010 at 08:12 AM.. Reason: Code tags, please.
# 5  
Old 02-23-2010
Grep:
Hello thillai,we can achieve it easily.

egrep "3|5" file


If you want to match more number of ids,you can give the ids with | operator in the grep pattern.
# 6  
Old 02-23-2010
Quote:
Originally Posted by vivekraj
Hello thillai,we can achieve it easily.

egrep "3|5" file


If you want to match more number of ids,you can give the ids with | operator in the grep pattern.
Dear vivek, Actually here you are matching the patterns from that file only. but that is not a actual requirement here. We need to Extract the pattern from the input file and we need to store it in a file separately.
# 7  
Old 02-23-2010
Using egrep command also you can achieve this.

The following contents are available in the file name file1. After execute the following command the output will go to the file new_file.

1 aaaaaa bbbcb cccccc
2 aaaaaa bbbbb cccccd
3 aaaaaa bbbab cccccc
4 aaaaaa bbbxb cccccc
5 aaaaaa bbbbb cwcccc
6 aaaaaa bbbbb cqcccc

Code:
egrep '3|5'  file1 > new_file

The output is

3 aaaaaa bbbab cccccc
5 aaaaaa bbbbb cwcccc
 
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