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Sed Command Issue

 
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# 1  
Old 11-05-2009
Sed Command Issue
Hello,

I want to remove the / found when executing the date command. When I use:
Code:
date +%D | sed 's/\///'

I get:
Code:
1105/09

I tried:
Code:
date +%D | sed 's/\*$///'

I need to remove all / from the date command, but it does not seem to work
Last edited by Yogesh Sawant; 02-26-2010 at 12:49 PM.. Reason: added code tags
# 2  
Old 11-05-2009
Code:
date +%D | sed 's/\///g'

# 3  
Old 11-05-2009
CPU & Memory
Scott's answer,
Code:
date +%D | sed 's/\///g'

is perfectly correct, but not as readable as
Code:
date +%D| sed 's-/--g

But why can't you just use
Code:
date +%m%d%y

?
Last edited by Yogesh Sawant; 02-26-2010 at 12:48 PM.. Reason: added code tags
# 4  
Old 02-26-2010
MySQL
See the following example code.
Code:
date +"%d/%m/%Y" | sed -e s%/%-%g

Code:
date +"%d/%m/%Y" | sed -e s#/#-#g

Code:
date +"%d/%m/%Y" | sed -e s@/@-@g


Output:
26-02-2010
# 5  
Old 02-26-2010
With out escaping the '/' you can achieve this by tr.Then why you preferred sed.

Code:
date +%D | tr "/" '\0'

# 6  
Old 02-26-2010
Code:
 date +%m%d%y

gives the identical results as
Code:
date+%D | sed 's/\///g'

 
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