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removing new line from the shell variable value


 
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# 1  
Old 10-07-2009
removing new line from the shell variable value

I have a small doubt that, how to chomp the new line from the bash shell variable value.

In perl, i will do chomp, but how to do it in bash -- shell programming.

When i redirect the date output i have a new line in it, which i would want to remove, how to do ?!
# 2  
Old 10-07-2009
Hope this helps,

Code:
#! /usr/bin/sh

b=`date`
echo -n $b

# 3  
Old 10-07-2009
Yep, am not going to just use that variable only for echoing.

Actually i would want to use in sed substitution, so how to remove that new line from the variable itself is the question.

Anyway, thanks for this response.
# 4  
Old 10-07-2009
Can you tell me what is the problem in your sed substitution.

Here's whatever I tried.
Code:
$ cat a
ASCII text
Wed Oct  7 05:53:51 PDT 2009 Test
1
2
3
4

$ cat b.sh
#!/usr/bin/sh

b=`date -d @1254920031`
sed  "s/${b}//" a

$ sh b.sh
ASCII text
 Test
1
2
3
4

It doesn't need chomping. Your case might be different. If you give wider data, it would be better to give solution.
# 5  
Old 10-07-2009
Yep, then it was my misunderstanding while reviewing that script.

Finally, i understood that date will not push newline. Thanks for all your response.
# 6  
Old 10-07-2009
Quote:
Originally Posted by thegeek
Yep, am not going to just use that variable only for echoing.
If your echo don't support -n option use printf.
 

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