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Deleting every other Line in VI


 
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# 1  
Deleting every other Line in VI

Hello,

How would one delete every other two lines using VI? For example, I have the following 8 lines:

Code:
Line1
Line2
Line3
Line4
Line5
Line6
Line7
Line8

And wish to only delete lines 3-4 and 7-8. Is there a certain pattern which would make this easier?


Thank you,

-Jahn
# 2  
dd ...
# 3  
Is there a way to do it from command mode? i.e., increase line position by two, delete two lines, increase line position, etc.

Thanks,

-Jahn
# 4  
nawk -f jahn.awk myFile
OR
nawk -v lines='1 4 8' jahn.awk myFile

jahn.awk:
Code:
BEGIN {
  if (!lines) lines="3 4 7 8"
  n=split(lines, lA, FS)
  for(i=1;i<=n;i++)
     linesA[lA[i]]
}
!(FNR in linesA)

# 5  
I get the following error:

Code:
awk: jahn.awk:3: fatal: split: second argument is not an array

Does 1A in this example need to be initialized as an empty array?

Thanks,

-Jahn
# 6  
am pretty confused, why you would want to this ?!

You have lot of ways to do that.. as
  • 3,4d
    • line ranged
  • macro
    • use vim macro to do it
# 7  
Quote:
Originally Posted by Jahn
I get the following error:

Code:
awk: jahn.awk:3: fatal: split: second argument is not an array

Does 1A in this example need to be initialized as an empty array?

Thanks,

-Jahn
copy/paste the posted code AS IS - 'lA' is NOT '1A'.
'lA' is ell-A, not one-A.
 

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