Help required on printing the line if third field is not a empty space


 
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# 1  
Old 08-10-2009
Help required on printing the line if third field is not a empty space

Hi Experts,

I want to print the lines whose third field in non-empty/blank space.

i.e.
INPUT FILE[/B]

dcdccghjrry0yd cont
dcdccttrk820529 cont rdekedfsSCr
dcdccttrdky2d0y cont rdekedfsSC2
dcdccghtd228e9y cont 2ekert5fr
dcdccght0er9r0d incont
dcdccght5dk9rre cont
dcdccttrdky200k incont rdekedfsSC2


[/U]OUTPUT FILE[/B]

dcdccttrk820529 cont rdekedfsSCr
dcdccttrdky2d0y cont rdekedfsSC2
dcdccghtd228e9y cont 2ekert5fr
dcdccttrdky200k incont rdekedfsSC2



I used below command, but it is printing some lines whose third field is empty/blank space i.e its not totally removing the lines whose third field is empty/blank.

awk '$3~/^[a-zA-Z0-9]/' inputfile > outputfile
# 2  
Old 08-10-2009
Try...

Code:
 
awk 'NF>2' inputfile

# 3  
Old 08-10-2009
Hi malcomex999,

When i executed awk 'NF>2' inputfile . i am getting ouput file same as input file. It is not working for my requirement.


INPUT FILE[/B]

dcdccghjrry0yd cont
dcdccttrk820529 cont rdekedfsSCr
dcdccttrdky2d0y cont rdekedfsSC2
dcdccghtd228e9y cont 2ekert5fr
dcdccght0er9r0d incont
dcdccght5dk9rre cont
dcdccttrdky200k incont rdekedfsSC2

OUTPUT FILE

dcdccghjrry0yd cont
dcdccttrk820529 cont rdekedfsSCr
dcdccttrdky2d0y cont rdekedfsSC2
dcdccghtd228e9y cont 2ekert5fr
dcdccght0er9r0d incont
dcdccght5dk9rre cont
dcdccttrdky200k incont rdekedfsSC2
# 4  
Old 08-10-2009
it should have worked unless the internal variable for the field separater is diiferent in ur shell...so try this....

Code:
 
awk -F " " 'NF>2' inputfile

 
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