UNIX for Dummies Questions & Answers

Hi,

I have a situation where I need to read a variable from another file. But the problem is that the variable in the other file is starting with $.

E.g.

file1:

$var1=out

temp_ss.sh:

. file1
echo "Print : $var1"

It works fine if the file1 is having var1=out (note that it is without $)
but the file will contain $ infront. Any thoughts?

Thanks
Shash

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Remove the $ in front of var1 in file1. Shell variables are defined without a $ in front of their name.

Apologies, I will keep that in mind.

Coming to the solution. I know that if we remove the $ in front of var1 from file1 it will work, but the problem is that the file will have a $ in front of each variable. Please help how to deal in this case.

Thanks
Shash

Then remove it before you source it? Or generate the file1 without the leading $. What help do you need?

I was wondering whether there is a way to ignore the $ after reading the file.

Code:

eval `tr -d '$' < file1`
echo $var

Thanks but it is not working if the file1 has something begining with square barcket.

Code:

[column]
$var1=test

---------- Post updated at 09:37 AM ---------- Previous update was at 08:42 AM ----------

I worked out by first selecting the records starting with $ and then using the code translate.

Thanks
Shash