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pick the very latest directory

 
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# 1  
Old 08-05-2009
pick the very latest directory
Hi,

I have some list of directories in the form datemonthyear e.g. 02082009, 03082009 and 04082009 etc.

I need to pick the latest directory from the current working directory.

Outcome:
05082009

This is the output am expecting.

Thanks
# 2  
Old 08-05-2009
Code:
jb>ls
02082009  03082009  04082009  05082009  25072009  30052009
jb>ls |sort -k1.5,1.8 -k1.3,1.4 -k 1.1,1.2 |tail -1
05082009
jb>

# 3  
Old 08-05-2009
Following should be close to what you're after:

1/ Assuming no other files or dirs, and if dirs were created on the same date as their name:

Code:
ls -t | sed q

will work

But depending exactly on what other dirs/timestamps etc you have there:
Code:
#  /bin/ls -l | awk '/^d/{print $9}' | sed 's/\(..\)\(..\)\(....\)/\3\1\2 &/g' | sort -nr | sed 's/[^ ]* //;q;'

should be reasonably clean and get you your answer.

HTH
# 4  
Old 08-05-2009
Thanks johnbach

One more query: can you interpret "sort -k1.5,1.8 -k1.3,1.4 -k 1.1,1.2"? i've gone through the man pages, but couldn't.
# 5  
Old 08-05-2009
-k1.5,1.8 means the data will be sorted for first field from 5th to 8th character.
So, suppose you have,

02082008
03082008
04082009
05082007

The output would be

05082007
02082008
03082008
04082009

The the second -k1.3,1.4 will sort for character 3 to 4...
and so on...

So he has first sorted for year then month and finally day.
# 6  
Old 08-05-2009
venkatesht,

Maybe this helps,

ls -lt |grep ^d |tail -1 |awk '{print $8}'
# 7  
Old 08-05-2009
thanks a lot rakeshawasthi
 
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