UNIX for Dummies Questions & Answers

hi friends

i am not getting any idea about how to implement the following with the help of SED cmd


1)need a sed command that deletes the first character in each line in a file


2)need sed command that deletes the character before the last character in each line in a file


3)need a sed command that swaps the first and second words in each line in a file



please help me

Give your input file and desired output if it is not a homework (I guess I had the same homework be4)

ok sir i agree with you; but i tried by using the following sed commands

1)$sed 's/^.//' myfile1
2)$sed 's/..$//' myfile1
3)$sed 's/ \([a-z]*\)/ \([a-z]*\)/ \2,\1' myfile1

NOte but i am not getting the required output plz help


my
given input file "myfile1" is as follows

root pts/1 july3109 192.200.200.9
cse1 pts/2 july3109 192.200.200.10
cse2 pts/3 july3109 192.200.200.11
cse3 pts/4 july3108 192.200.200.12


output to be required is (using sed commads):
1) delete the first character in each line of the above input file
2)and deletes the character before the last character in each line of the above file
3)swap the first and 2nd words in the above file

1. What do you mean by "word"? If you mean strictly alphabetic characters then the first line has the first word as "root" and the second word as "pts", but the second line has the first word as "cse" and the second word as "pts." Is this really what you want? Perhaps you really mean "swap the first and 2nd fields delimted by whitespace."

2. I'm guessing you are deleting the last two characters of the line instead of just the last character. It would help if you posted the output you are getting as well as the additional information other repliers have suggested.

3. Your command to swap words has other problems besides the lack of a definition for what a word is. Do you really want to insert a comma in the output between the swapped words? I don't see that requirement in your list. Also, s command for swapping should have given you a "command garbled" message from sed because you either

a. did not escape the "/" or
b. you have extra characters after the final "/" of the sed command. The form of your 3rd sed command should be the same as the first two.

i am not getting sed

Your 1st command works fine:

[aaaa@xxxx] $ cat file
root pts/1 july3109 192.200.200.9
cse1 pts/2 july3109 192.200.200.10
cse2 pts/3 july3109 192.200.200.11
cse3 pts/4 july3108 192.200.200.12

[aaaa@xxxx] $ sed 's/^.//' file
oot pts/1 july3109 192.200.200.9
se1 pts/2 july3109 192.200.200.10
se2 pts/3 july3109 192.200.200.11
se3 pts/4 july3108 192.200.200.12

sed fullform is stream editor cmd i want sed instruction(command) for the earlier query