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Create file with column values


 
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# 1  
Old 06-02-2009
Create file with column values

Hi,

I have a data file looks like the following

Code:
ID      STARTDATE       ENDDATE
101     20090520        20090521
102     20090521        20090522
103     20090522        20090523
104     20090523        20090524
105     20090524        20090525
106     20090525        20090526
107     20090526        20090527
108     20090527        20090528

Now i want to create a text file eg., data_STARTDATE_ENDDATE.txt
for each ID in the data file.
I am working on the script but with no result Smilie

Last edited by Don Cragun; 06-06-2016 at 01:18 AM.. Reason: Add CODE and ICODE tags.
# 2  
Old 06-02-2009
Quote:
Originally Posted by naveen.kuppili
I am working on the script but with no result Smilie
Did you get errors? Why don't you show us your script?
# 3  
Old 06-02-2009
Code:
#! /bin/ksh
i="1"
while read line
do
x=`awk -v num="$i" '{if(NR==num) print($2);}' mvm.txt`
y=`awk -v num="$i" '{if(NR==num) print($3);}' mvm.txt`
case $x in +([0-9])*(.)*([0-9]) )
        touch mvm_file_"$x"_"$y".txt
        ;;
        * )
        ;;
esac
i=`expr $i + 1`
done < mvm.txt

Yes i worked on it and is solved.

Last edited by Don Cragun; 06-06-2016 at 01:19 AM.. Reason: Add CODE tags.
# 4  
Old 06-02-2009
if you have Python , and assuming each ID is unique
Code:
f=open("file")
firstline = f.readline()
for line in f:
    oline=line
    line= line.strip().split()
    open("data_"+line[1]+"_"+line[2],"a").write(oline)

output
Code:
# ./test.py
# ls -1 data_*
data_20090520_20090521
data_20090521_20090522
data_20090522_20090523
data_20090523_20090524
data_20090524_20090525
data_20090525_20090526
data_20090526_20090527
data_20090527_20090528

 

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