UNIX for Dummies Questions & Answers

How can I find find all members in the /etc/password file that belong to the dba group in the /etc/group file?

I don't have a box in front of me, but maybe you could post a couple sample lines from each one? Also, what system/shell do you use?

It'd have to be something like:

Code:

awk '{print $1}' < /etc/group |
while read USR
do
 grep $USR /etc/password
done

where $1 is the field the username is in, inside the /etc/group file...

if the /etc/group file looks like:
xxx xxx jsmith xxx
then you'd use {print $3}

Thanks!

i use ksh
here's a few lines from /etc/group
root::0:root
other::1:root,hpdb
bin::2:root,bin
sys::3:root,uucp
dba::101:

here's a fre lines from /etc/passwd

root:IVDV6376kipOA:0:3::/:/sbin/sh
bin:*:2:2::/usr/bin:/sbin/sh
sys:*:3:3::/:
oracle:rbQbnl8j2tfx6:101:101:,,,:/oratest2/u01/app/oracle:/bin/gsh
bmc:xbYoHEN598qAc:141:20:BMC Group Id,,,:/home/bmc:/bin/gsh
joew:UpWBpbMeEg/WM:20828:101:Joe West:/home/jwest:/bin/gsh

Hhhm, let's start a perl course

Code:

#!/usr/local/bin/perl

$dba="101";

open(FH, "< /tmp/passwd");
@lines=<FH>;
close(FH);

foreach $line(@lines) {
  $group = ( split /:/, $line)[3]; 
  if ( "$group" == "$dba" ) {
    print "Group is DBA \n";
    print "$line \n";
  }
}

It's tested and works !!

Regs David

And if you still want to try awk:

Code:

awk -F":" '{print $1}' < /etc/group |
while read USR
do
 grep $USR /etc/password
done