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Integer check (again)...

 
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# 1  
Old 03-02-2009
Integer check (again)...
I have search the forum for an easier way to write this code. I have two separate 'if' to do this and it works but am wondering if someone knows a quick way to combine them. I want anything between 1 and 100 but not '01' or '005', '0010', etc.

Code:
     

if [[ $myvar != +([0-9]) ]] ||
   [[ $myvar -le 0 || $myvar -gt 100 ]]; then
   echo "Try again"
fi

After that check, I do another check with a grep to make sure it doesn't start with a zero (so this is the 'else' block of the above code):

Code:
if echo $myvar | grep '^[1-9][0-9]*'; then 
   echo "Cool"
fi

Any thoughts?
# 2  
Old 03-02-2009
Try this :

Code:
while read myvar
do
   if [[ $myvar -eq 0 ]] || [[ ${myvar%"${myvar#?}"} != 0 && $myvar -gt 0 && $myvar -le 100 ]]
   then
      echo "Ok"
   else
      echo "Not Ok, try again" 
   fi
done

# 3  
Old 03-02-2009
Code:
#!/bin/ksh

case ${myvar} in
   @(0*|*[!0-9]*)    ) echo 'bad' ;;
   @([0-9]|[0-9][0-9]|100) ) echo 'good' ;;
                    *) echo 'bad' ;;
esac

# 4  
Old 03-02-2009
Thank you. These are simpler than what I have. Both solutions worked. The only caveat is that the first solution can case the program to terminate if a user input happens to include any non-numeric character. If you can control that then it's fine.

The second solution covers all basis as far as my testing went.
 
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