ksh script


 
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# 8  
Old 05-30-2003
Thank you all, for your respones. After days of headache I found a solution; I just creat a array and put every thing in until I get to the number I'm looking for and then just take it back out (in reverse order) until I get to a 0000 number in which I stop. It would be easy in C or C++ with a stack( using push and pop ) but in script there isn't any push or pop that I know of. If any one would like to look at the script. Let me know I will post it. Thanks again
# 9  
Old 06-11-2003
Quote:
Originally posted by larry
Thank you all, for your respones. After days of headache I found a solution; I just creat a array and put every thing in until I get to the number I'm looking for and then just take it back out (in reverse order) until I get to a 0000 number in which I stop. It would be easy in C or C++ with a stack( using push and pop ) but in script there isn't any push or pop that I know of. If any one would like to look at the script. Let me know I will post it. Thanks again

HI
I think you are correct. Please post your shell script.I want to have a look at your shell script.

What my suggestion is store the size of the array in a variable and display it till you reach a specified number.
# 10  
Old 06-12-2003
Here is the script. I hope this is helpful to everyone.
Code:
#!/bin/ksh
#
#
#Getting information into the array

index=0
look=$1
while read snumber
do
   if [ $snumber = $look ]
   then
       c_array[$index]="$snumber"
       break
  else
       c_array[$index]="$snumber"
       index=`expr $index + 1`
  fi
done < file_name


#Getting information out of the array

indeo=${#c_array[*]}
while (( $indeo > 0 ))
do
   if [[ ${c_array[$indeo]} = "0000" ]]
   then
      echo ${c_array[$indeo]}
      break
  else
      echo ${c_array[$indeo]}
      indeo=`expr $indeo -1`
   fi
done

exit 0
###########

this is works for me but if anyone see any improvement please tell me.

I added code tags for readability...Perderabo

Last edited by Perderabo; 06-12-2003 at 06:48 PM..
# 11  
Old 06-12-2003
If raw ksh is required, I guess the OP's final solution was fine. In awk:
Code:
nawk -v sought=0005 '/^[1-9]/ { i=0 }
/^0/ { a[++i] = $0 }
$1 == sought { for (j=1; j<=i; j++) print a[j] }'

This restarts accumulating lines whenever the number on a line doesn't start with zero. It gathers all the lines that start with zero, then when it sees the number "sought", it prints the numbers that have accumulated since the last non-zero.

If a group contains more than one copy of the number sought, you may not get the expected result. There are other gotchas as well, to get around them requires more code and some knowledge about the shape of your data. More work is also required if there is more than one group that contains your number and you want a blank line between, etc.
 
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