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awk with (if condition)


 
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# 8  
Old 05-01-2020
Quote:
Originally Posted by RudiC
Try this:
...
Name unquoted is an uninitialized variable name defaulting to "". Any empty $1 in sight?
And that is why I dont understand why $1 == Name removes the "Name" line and shows the remaining values...
Because $1 is not empty -> it contains 'Name'... (and then the names...)

Cant wrap my head around that.
(can you 'follow' my confusion?)

And the TO did/does not want the header-line shown, that is why I settled for $1 ==! "Name"
# 9  
Old 05-01-2020
Quote:
Originally Posted by sea
And that is why I dont understand why $1 == Name removes the "Name" line and shows the remaining values...
It doesn't. It would remove any line with an emtpy $1, of which there is none. You can leave it out entirely. The $4 < 7000 removes the header line. $4 > 7000 would not; we'd need a different criterion, then.



Quote:
And the TO did/does not want the header-line shown, that is why I settled for $1 ==! "Name"
Hmm - that ==! is a construct that I can't get my head around. It obviously is a correct syntax - no complaints by the interpreter. So the == must be separated from the ! which then logically negates the NAME variable's contents and results in a 1 or 0 which in turn is tried to be matched against $1. And, so it is. Add a line starting with a 0 or 1 and see what's going to happen.
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