Hello to all,
I'm working on a file that contains a series of decimal values with different precision.
I need to divide these numbers by 100 and I don't need to round.
Input file: output: I would like not to round the result and get the following output:
Thanks in advance
Last edited by vgersh99; 04-22-2020 at 11:02 AM..
Reason: code tags, please!
Decimal numbers represented by a binary system are ALWAYS rounded / subject to rounding. For example, your first number, given as 0.123456789012, is internally approximated / stored as 0.123456789011999995553381381796, which itself is a rounded value already. You may end up less than or greater than your target value, or, in rare cases, exactly on target (0.5, or 0.25, for example).
So, your request is a bit diffucult to fulfill. You can try awk's OFMT variable set to a fixed output field length, but, surprise, additional undesired decimal places occur:
If that is unsatisfying, you can resort to formatted print and a tricky taylored field length computation:
This works as there are two additional places needed for the division by 100, but length ($1) already counts two characters: the leading 0 and dot. If you have more significant leading digits, additional measures / steps need to be taken.
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Hi.
This might possibly be done for the range of numbers noted by parsing the numbers, inserting 2 zeros, and so avoiding any arithmetic whatsoever -- just a thought ... cheers, drl
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
Hi Friends,
I have an input file like this
cat input
chr1 100 200 1 2
chr1 120 130 na 1
chr1 140 160 1 na
chr1 170 180 na na
chr1 190 220 0 0
chr1 220 230 nd 1
chr2 330 400 1 nd
chr2 410 450 nd nd
chr3 500 700 1 1
I want to calculate the division of 4th and 5th columns. But, if... (3 Replies)
I have some calculation in my script which is similar to the below example . I find that sometimes when using large decimal digits, the output gets automatically rounded off and it is affecting the program. I am not able to understand what is happening here..
awk '{
a=6.32498922
a1=6.324... (5 Replies)
vmstat|awk '{print $3}'|tail -1
returns 6250511, but what I need is 24416, which is 6250511 divided by 256.
Please advise.
Thank you so much (2 Replies)
I had a person bring an interesting problem to me that appears to involve some sort of rounding inside awk. I've verified this with awk and nawk on Solaris as well as with gawk 3.1.5 on a Linux box.
The original code fragment he brought me was thus:
for (index=0; index < 1; index=index+.1)
... (4 Replies)
I received error "awk: division by zero" while executing the following statement.
SunOS 5.10 Generic_142900-15 sun4us sparc FJSV,GPUZC-M
echo 8 | awk 'END {printf ("%d\n",NR/$1 + 0.5);}' file1.lst
awk: division by zero
Can someone provide solution?
Thanks
Please use code... (11 Replies)
Hi,
I have managed to round up numbers by using the following command:
echo "5.54" | awk '{printf "%.0f\n", $1}'
result
6
How can I round up all the numbers in a column in a file and print the lines with the new calculated totals?
Thanks, (3 Replies)
I need to read the file divide 3 column with 2nd and run a modulus of 10 and check whether the remainder is zero or not if not print the entire line.
cat filename | awk '{ if ($3 / $2 % 10 != 0) print $0}'
Whats wrong with it ? (4 Replies)
Hi Friends,
I am trying to round following number.
0.07435000
echo "0.07435000"|awk '{printf "%s\n",$1*100}'|awk '{printf "%.2f\n",$1}'
It returns: 7.435
It should return: 7.44
Any suggestion please?
Thanks,
Prashant (2 Replies)
Hello
I am getting this very annoying issue in awk:
awk '{a=12825;b=a*1.25; print b}' test
16031.2
Thing is the multiplication result is wrong... Result should be 16031.25.
I think the issue only happens on bigger numbers.
What can I do to get passed this?
Thanks by advance (3 Replies)