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Help in parsing expect command's output and remove new lines EXPECT scripting

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# 1  
Old 04-16-2020
Help in parsing expect command's output and remove new lines EXPECT scripting
I am new to expect scripting.

Code:
expect "# " {send "hostname -i\r"}
expect {
    -re "\r(.*)#" {set addr1 $expect_out(1,string)}
}

addr1 prints -
Code:
hostname -i
111.22.33.444

How do i get just 111.22.33.444 without any trailing new lines?

Thanks in advance

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!
Last edited by RavinderSingh13; 04-17-2020 at 12:19 AM..
# 2  
Old 04-16-2020
Your RE is matching the local echo of hostname -i\r sent earlier. Try this RE .*\r\n(.*)\r\n#

For example:
Code:
set timeout 3
log_user 0
expect "# " {send "hostname -i\r"}
expect {
   -re ".*\r\n(.*)\r\n# " {set addr1 $expect_out(1,string)}
   timeout { puts "Timeout looking for TCP/IP address\n"; }
}
send "exit\r"

puts "TCP/IP address is: $addr1"

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