Creating values based on position


 
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# 8  
Old 03-11-2020
Try:
Code:
awk -F, '$3=="bcd"{$0=$0 FS substr($NF,4,1)}1' file

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# 9  
Old 03-13-2020
Thanks for helping out. Solution worked perfectly. Is there a way to fetch and create value from last column of 9th char if 3rd column is not "bcd",it would be better if we can add both condition in one command. I tried with "!" but that doesn't help.
# 10  
Old 03-13-2020
Hi, @zooby
pay attention to the previous post #8
it will be enough for you to replace == with != and instead of 4 use the number 9
if of course I understood everything correctly

--- Post updated at 16:59 ---

Together it will look like this
Code:
awk -F, '
$3=="bcd"    {$0=$0 FS substr($NF,4,1)}
$3!="bcd"    {$0=$0 FS substr($NF,9,1)}
1' file

--- Post updated at 17:22 ---

Code:
sed -r 's/^([^,]*,){2}bcd,.*,(.){4}.*/&,\2/;t1; s/.*,(.){9}.*/&,\1/;:1' file


Last edited by nezabudka; 03-13-2020 at 10:29 AM..
# 11  
Old 03-13-2020
Or
Code:
awk -F, '
    {print $0 FS substr($NF,($3=="bcd") ? 4 : 9, 1)}
' file

This User Gave Thanks to RudiC For This Post:
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