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Grep lines between two specific words after matching pattern


 
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# 1  
Grep lines between two specific words after matching pattern

grep specific number of lines from file after matching pattern
Quote:
Line 1
.
.
.
Start
.
.
12345
.
.
End
.
.
Line n
I want to grep all the lines between keyword 'start' to 'end' after matching pattern/ number 12345

Is it possible?
Thanks in advance
# 2  
Assuming Linux:
Code:
a=3
b=3
grep -A$a -B$b  '12345'  somefile

This searches from 3 lines before and 3 line after the keyword is found. Total 7 lines, including keyword '12345'
# 3  
Quote:
Originally Posted by sagar_1986
grep specific number of lines from file after matching pattern
I want to grep all the lines between keyword 'start' to 'end' after matching pattern/ number 12345

Is it possible?
Thanks in advance
Hello sagar_1986,

Could you please do share your efforts which you have put in order to solve your own problems?
We encourage users to learn coding on this forum, so please do share so.

Thanks,
R. Singh
# 4  
Hello RavinderSingh13 ,


Actually i know how to get 'n' ( fixed) number of lines before and after the matching pattern, but here the issue is that position of 'start' and 'end' is not fixed.
Here i want to grep first occurrence of 'start' before matching pattern and first occurrence of 'end' after matching pattern and i don't have any idea how to do this, could you please help.
# 5  
Quote:
Originally Posted by sagar_1986
Hello RavinderSingh13 ,
Actually i know how to get 'n' ( fixed) number of lines before and after the matching pattern, but here the issue is that position of 'start' and 'end' is not fixed.
Here i want to grep first occurrence of 'start' before matching pattern and first occurrence of 'end' after matching pattern and i don't have any idea how to do this, could you please help.
Hello sagar_1986,

Again you are missing the point, request to you is to add your efforts in form of code; so kindly do so and let us know then.

Thansk,
R. Singh
# 6  
Code:
awk '/start/{flag=1} flag; /end/{flag=0}' sample.txt

Quote:
...... this prints all the start..end combinations
Code:
awk '/start/,/123456/,/end/'  sample.txt 
sed '/start.*123456.*end/!d' sample.txt
sed -n '/start.*123456.*end/p' sample.txt

Quote:
only two matching patterns are allowed in this command cant insert third matching pattern.
Code:
sed -e '/./{H;$!d;}' -e 'x;/123456/!d; sample.txt'

Quote:
..... this prints entire document as there is no paragraph in doc.
Code:
sed -e '/./{H;$!d;}' -e 'x;/start/!d;/123456/!d;/end/!d' sample.txt

Quote:
.....this also does the same as there is not paragraph.
so how to get lines which contains three matching patterns
This User Gave Thanks to sagar_1986 For This Post:
# 7  
You can see one way of doing on post #2

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