How to ignore mutiple strings when using shell script?


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# 1  
How to ignore mutiple strings when using shell script?

Hi All,

I am trying to use below syntax to find ignore multiple locations while searching for a file.

Code:
find / -name "$serviceitem" ! -size 0  2>&1 |egrep -v "tmp|docker|WinSxS|Permission|HISTORY|alternatives|bearer11ssl|manifest"

I tried to assign all the ignore strings to one variable like below

Code:
ignore_list=`tmp|docker|WinSxS|Permission|HISTORY|alternatives|bearer11ssl|manifest`
find / -name "$serviceitem" ! 2>&1 |egrep -v "$ignore_list"

But it's throwing error.

Can someone please let me know how to use the above syntax.
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Last edited by RavinderSingh13; 02-06-2020 at 09:46 PM..
# 2  
You want alternation:
Code:
find / -name "$serviceitem" ! -size 0  -exec egrep -v "(tmp|docker|WinSxS|Permission|HISTORY|alternatives|bearer11ssl|manifest) \;"


Last edited by RavinderSingh13; 02-07-2020 at 12:01 AM..
# 3  
Hi
Replace backquotes with single quotes
Code:
ignore_list=`tmp|docker|WinSxS|Permission|HISTORY|alternatives|bearer11ssl|manifest`

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