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Discarding records with duplicate fields


 
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# 1  
Old 02-03-2020
Discarding records with duplicate fields

Hi,

My input looks like this (tab-delimited):
Code:
grp1	name2	firstname	M	55	item1	item1.0
grp1	name2	firstname	F	55	item1	item1.0
grp2	name1	firstname	M	55	item1	item1.0
grp2	name2	firstname	M	55	item1	item1.0

Using awk, I am trying to discard the records with common fields 2, 4, 5, 6, 7 only for records from 'grp2' (field $1; i.e. records starting with 'grp1' should be kept no matter what) in order to get this output:
Code:
grp1	name2	firstname	M	55	item1	item1.0
grp1	name2	firstname	F	55	item1	item1.0
grp2	name1	firstname	M	55	item1	item1.0

Here is my code, but I don't see what is wrong with it.
Code:
awk '
BEGIN{FS=OFS="\t"}
{
    a[$2 FS $4 FS $5 FS $6 FS $7]

    if($1 ~ /grp2/){
        if(a[$2 FS $4 FS $5 FS $6 FS $7]++==0){
            print $0
         }
    }
    else{
        print $0
    }
}' input.tab

Any help would be greatly appreciated.
# 2  
Old 02-03-2020
Hello beca123456,

Could you please try following.

Code:
awk '/^grp1/{print;a[$2,$4,$5,$6,$7]++;next} !a[$2,$4,$5,$6,$7]++'   Input_file

Output will be as follows.

Code:
grp1    name2   firstname       M       55      item1   item1.0
grp1    name2   firstname       F       55      item1   item1.0
grp2    name1   firstname       M       55      item1   item1.0

Thanks,
R. Singh
# 3  
Old 02-03-2020
Your code works. Thanks !
But I would like to understand why mine does not. It seems fine to me...
# 4  
Old 02-03-2020
Quote:
Originally Posted by beca123456
Your code works. Thanks !
But I would like to understand why mine does not. It seems fine to me...
Hello becal123456,

IMHO problem in your code is that you haven't done any increment on very first occurrence of a[$2 FS $4 FS $5 FS $6 FS $7] and when it goes into condition check happens first and increment for that line's field happens later hence false positive results are coming, so if you change your code to following:

Code:
awk '
BEGIN{FS=OFS="\t"}
{
    a[$2 FS $4 FS $5 FS $6 FS $7]++
    if($1 ~ /grp2/){
        if(a[$2 FS $4 FS $5 FS $6 FS $7]==1){
            print $0
         }
    }
    else{
        print $0
    }
}'   Input_file

Then we are doing increment in array a[$2 FS $4 FS $5 FS $6 FS $7]++ so when it goes to next time in grep2 condition it has those values also which are common in grep1 line(which were getting missed since we haven't put increment in its previous statement).

I hope we should be good here, please feel free to shoot any further queries on same.

NOTE: To say anyone "Thanks" on UNIX.com you can hit THANKS button; present at every post's left corner Smilie

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 5  
Old 02-03-2020
I see my mistake. Thanks !

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