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How to split the string value to an array?

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# 8  
Old 01-20-2020
Or so it's easier and more understandable matrix creating
Code:
declare -A store
eval store=($(awk '{for(i=1;i<=NF;i++) print "[" NR "," i "]=" $i}' $filename))

Last edited by nezabudka; 01-20-2020 at 05:21 AM..
# 9  
Old 01-21-2020
It should work the same way on both the "bash" and the "ksh93"
Code:
cat file
tom is hot
one two three
four five six

Code:
set -A store
#declare -A store
eval "store=($(awk '{for(i=1;i<=NF;i++) print "[" NR "." i "]=" $i}' file))"

print first line. you can even take ten with a margin
Code:
eval echo '${'store[1.{1..10}]}
tom is hot

revers
Code:
eval echo '${'store[1.{10..1}]}
hot is tom

output 2 columns
Code:
eval echo '${'store[{1..10}.2]}
is two five

odd lines
Code:
eval echo '${'store[{1..10..2}.{1..10}]}
tom is hot
four five six

#Change case of all first characters of the first line (only bash. I just do not know the options for ksh93)
Code:
#eval echo '${'store[1.{1..10}^]
#Tom Is Hot

print only the first characters of all values
Code:
eval echo '${'store[{1..10}.{1..10}]:0:1}
t i h o t t f f s

print only the last characters of all values
Code:
eval echo '${'store[{1..10}.{1..10}']:\(-1\)}'
#eval echo \${store[{1..10}.{1..10}]:\(-1\)} #for bash
m s t e o e r e x

leave one character in words with an odd number of letters
Code:
eval echo '${'store[{1..10}.{1..10}]//??} #for visibility replace with a plus //??/+}
m t e o e x

And here accuracy is already needed. Determine the length of each value
Code:
eval echo '${'#store[{1..3}.{1..3}]}
3 2 3 3 3 5 4 4 3

These 2 Users Gave Thanks to nezabudka For This Post:
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