Insert year in ls -l command


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# 8  
Hello kumarinfa,

For Thanking someone on Unix.com you could HIT THANKS button at the left corner of each post.

For your other question in your previous post, I believe my same command should work, though I made a small change in it, try following and let me know then.

Code:
awk '{split($NF,array,"[_]");$NF=array[2] OFS $NF} 1'  Input_file

Thanks,
R. Singh
# 9  
Sure Ravinder,

The new filename is :
Code:
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 12312019 file1_12312019_062449.csv

and the awk command will extract whole set of string i.e "12312019" for $NF=array[2], rather i need this substr(5:8) i.e. "2019" . In my earlier input i had only 2019 as second field but in this ihave date and month too. So i am not getting how to extract last 4 chars from array[2].
# 10  
Quote:
Originally Posted by kumarinfa
@Jim,

Thanks for your reply, and yes i am well aware about DATE command and its relevant formats, kindly follow my first post carefully as i mentioned that i cannot use any ls options because i am getting file listing from ftp server. Is there any command which can give me desired result directly from ftp while using ls?

TIA

--- Post updated at 07:10 PM ---

Thank you @Ravinder,

I understood very well what you explained. Also can you tell me what if i have to extract year if i get input like this:

Code:
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 12312019 file1_12312019_062449.csv

Here 2019 is not whole word rather part of second field, tried using substr but not able to get the idea that how to nest split and substr function.

TIA
Code:
perl -ple 's/\w+?(\d{4})[._]/$1 $&/' kumarinfa.file

Output:
Code:
-rw-r--r--    1 360      600         94255 Jan 01 11:16  2020 file1_2020.csv
-rw-r--r--    1 360      600        114573 Dec 29 11:10  2019 file2_2019.csv
-rw-r--r--    1 360      600         41006 Dec 30 11:09  2019 file3_2019.csv
-rw-r--r--    1 360      600        165923 Dec 31 11:29  2019 file4_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29  2019 file1_12312019_062449.csv

Code:
awk '
{
  split($NF,array,"[_.]")
  yyyy = substr(array[2], length(array[2])-3)
  $NF=yyyy OFS $NF
}1' kumarinfa.file
-rw-r--r-- 1 360 600 94255 Jan 01 11:16 2020 file1_2020.csv
-rw-r--r-- 1 360 600 114573 Dec 29 11:10 2019 file2_2019.csv
-rw-r--r-- 1 360 600 41006 Dec 30 11:09 2019 file3_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 2019 file4_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 2019 file1_12312019_062449.csv

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