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# 1  
Print strings from a particular position in each line

I am using bash in Fedora 30

From the below lines (ls -l output), how can I print whatever is between the strings 'status_' and '.log'

Code:
$ ls -l | grep -i status 
-rw-rw-r--. 1 sysadmin sysadmin 378530 Nov 11 21:58 status_vsbm1.log
-rw-rw-r--. 1 sysadmin sysadmin 428776 Nov 11 21:58 status_OSMPRD1.log
-rw-rw-r--. 1 sysadmin sysadmin 393977 Nov 11 21:58 status_fxmdbp1.log
-rw-rw-r--. 1 sysadmin sysadmin 557476 Nov 11 21:58 status_cgsm1.log
-rw-rw-r--. 1 sysadmin sysadmin 555879 Nov 11 21:58 status_cgsm2.log
-rw-rw-r--. 1 sysadmin sysadmin 553381 Nov 11 21:58 status_cgsm3.log
-rw-rw-r--. 1 sysadmin sysadmin 556506 Nov 11 21:58 status_cgsm4.log
-rw-rw-r--. 1 sysadmin sysadmin 577325 Nov 11 21:58 status_cgsm5.log
-rw-rw-r--. 1 sysadmin sysadmin 415795 Nov 11 21:58 status_SOACAT1.log
-rw-rw-r--. 1 sysadmin sysadmin 449812 Nov 11 21:58 status_INTPHLK11.log
-rw-rw-r--. 1 sysadmin sysadmin 455842 Nov 11 21:58 status_INTPHLK21.log
-rw-rw-r--. 1 sysadmin sysadmin 447726 Nov 11 21:58 status_wmeaidbp1.log
-rw-rw-r--. 1 sysadmin sysadmin 385274 Nov 11 21:58 status_wmsmpdbp1.log
$

Expected output :

Code:
vsbm1
OSMPRD1
fxmdbp1
cgsm1
.
.
.

# 2  
there are probably a million ways to do it more elegantly but I would probably just try this
Code:
ls -ali | rev | cut -d' ' -f 1 | cut -c 1-7 | cut -c 5-99 | rev

# 3  
Something like this, also not very elegant:

Code:
ubuntu# egrep -o '_.*[0-9]' test.log | cut --complement -c  1
vsbm1
OSMPRD1
fxmdbp1
cgsm1
cgsm2
cgsm3
cgsm4
cgsm5
SOACAT1
INTPHLK11
INTPHLK21
wmeaidbp1
wmsmpdbp1

Or, in your case:

Code:
ls -l | grep -i status  | egrep -o '_.*[0-9]'  | cut --complement -c  1

There must be 100s of ways to do this which are much nicer ... LOL

Like ...

Code:
ls -l | egrep -o 'status_.*[0-9]' | cut --complement -c1-7

PS: kraljic .... You should really try yourself (post code) when asking a question like this. Show your work and what you tried yourself. You have over 100 posts here. Try yourself before asking, please.
This User Gave Thanks to Neo For This Post:
# 4  
Two stage process not using ls:
Code:
for f in status_*.log
do
   f1="${%*_}
   printf "%s\n" "${f1#.log}"
done

Which can be written as a single line:
Code:
for f in status_*.log; do f1="${%*_}; printf "%s\n" "${f1#.log}"; done

# 5  
Code:
ls | sed -n 's/^status_\(.*\)[.]log$/\1/p'

These 2 Users Gave Thanks to MadeInGermany For This Post:
# 6  
Code:
ls | awk -F"status_|[.]log" ' { print $2 } '

This User Gave Thanks to anbu23 For This Post:
# 7  
Using external programs (such as cut, *grep,sed,awk or others) are a dire waste of precious resources as well as processes.


Quote:
Originally Posted by anbu23
[
Code:
ls | awk -F"status_|[.]log" ' { print $2 } '

Quote:
Originally Posted by zxmaus
Code:
ls -ali | rev | cut -d' ' -f 1 | cut -c 1-7 | cut -c 5-99 | rev



It is not clear what the two revs should accomplish, except making the line non-standard and GNU-dependant.



Quote:
Originally Posted by Neo
Code:
ubuntu# egrep -o '_.*[0-9]' test.log | cut --complement -c  1

Code:
ls -l | egrep -o 'status_.*[0-9]' | cut --complement -c1-7


This is using several non-standard GNU-specific extensions and will therefore only work with the GNU versions of the used utilities. It is dangerous to suggest such solutions, at least when foregoing a proper disclaimer that it won't work in most environments.


Quote:
Originally Posted by apmcd47
Code:
for f in status_*.log; do f1="${%*_}; printf "%s\n" "${f1#.log}"; done


This is - in principle - a valid solution although it seems the "#" and "%" operators have been confused, a double quote is missing and a few typos like
Code:
f1="${%*_}

will prevent proper execution. It is not necessary to use different variables for the expansion either:



Code:
for f in status_*.log; do f="${f%.log}"; printf "%s\n" "${f#status_}"; done

These 2 Users Gave Thanks to foad For This Post:

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