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Awk/sed to replace variable in file

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# 8  
Old 11-18-2019
A little clumsy as you have to take care for every single special case - may benefit from some polishing:
Code:
awk '
BEGIN   {PAT = "<<[^>]*>>"
        }

        {match ($0, PAT)
         NXT = RSTART + RLENGTH
         FN = substr ($0, RSTART+2, RLENGTH-4)
         while (0 < getline T1[++CNT1] < FN );
         close (FN)
         match (substr ($0, NXT), PAT)
         FN = substr ($0, NXT+RSTART+1, RLENGTH-4)
         while (0 < getline T2[++CNT2] < FN );
         close (FN)

         if (CNT1==1)   print
         else           for (i=1; i<CNT1; i++)   if (CNT2>1)    for (j=1; j<CNT2; j++)  {TMP = $0
                                                                                         sub (PAT, T1[i], TMP)
                                                                                         sub (PAT, T2[j], TMP)
                                                                                         print TMP
                                                                                        }
                                                 else                                   {TMP = $0
                                                                                         sub (PAT, T1[i], TMP)
                                                                                         print TMP
                                                                                        }
         CNT1 = CNT2 = 0
        }
' file


@nezabudka: nice, witty solution! But - shouldn't it be print $1 d $3 b $5 in lieu of what is in your post?
Last edited by RudiC; 11-19-2019 at 08:32 AM.. Reason: Closed 2nd FN too early - corrected.
This User Gave Thanks to RudiC For This Post:
nezabudka
# 9  
Old 11-22-2019
Thanks All
i was able to write my code in shell script via loop and it is working fine/expected.
will share that code
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