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If file pattern exists in directory then continue

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# 1  
Old 11-15-2019
If file pattern exists in directory then continue
he below looks in $dir for any pattern of fileone. As is, it executes but only returns File found if the exact format in the script exsists. Why isn't a pattern of fileone being looked for and if it is in [CODE]$dir[/ICODE], File found. I think that is what should happen. Thank you Smilie.


Code:
dir=/path/to
if ls "$dir"/fileone.csv* > /dev/null 2>&1
then
    echo "File not found!" >> "$dir"/log && exit 0
else
    echo "File was found, moving on " >> "$dir"/log
fi

Last edited by cmccabe; 11-15-2019 at 04:37 PM.. Reason: fixed format
# 2  
Old 11-15-2019
Don't understand. Above will echo "File not found!" if any file name beginning with fileone.csv exists in dir, like
Code:
fileone.csv
fileone.csv12
fileone.csvacbdefaj
fileone.csv_sdfwegf

If none of those or alike exist, it will echo "File was found, moving on ".
This User Gave Thanks to RudiC For This Post:
cmccabe
# 3  
Old 11-15-2019
If any of the below are in $dir then File found was found, moving on.

Code:
fileone.csv
fileOne.csv
Fileone.csv
FileOne.csv

If none of those or alike exist, it will echo "File was found and exit. The pattern will always be fileone.csv just the case may be different. Maybe there is a better way? Thank you Smilie.
# 4  
Old 11-16-2019
Quote:
Originally Posted by cmccabe
... If none of those or alike exist, it will echo "File was found and exit ...
Please take care when formulating your request. Misleading specifications may lead to unsatisfactory proposals.





Try
Code:
if ls "$dir"/[Ff]ile[Oo]ne.csv > /dev/null 2>&1
  then  echo "File was found, moving on "
  else  echo "File not found!"
fi

This User Gave Thanks to RudiC For This Post:
cmccabe
# 5  
Old 11-16-2019
Define a file_exists function.
Then you can do
Code:
if file_exists "$dir"/[Ff]ile[Oo]ne.csv
then
...

This User Gave Thanks to MadeInGermany For This Post:
cmccabe
# 6  
Old 11-18-2019
Thank you both Smilie.
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