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Extract a part of grep output

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# 1  
Old 10-24-2019
Extract a part of grep output
Hi,
On AIX 7
I have :
Code:
grep 's_ohs_instance_loc' $CONTEXT_FILE
        
<ohs_instance_loc oa_var="s_ohs_instance_loc">/u01/appl_top/env/fs1/FMW_Home/webtier/instances/EBS_web_env_OHS1</ohs_instance_loc>

But I need only this part: /u01/appl_top/env/fs1/FMW_Home/webtier/instances/EBS_web_env_OHS1

which is between > and < How can I have it?

Thanks
Last edited by Yoda; 10-24-2019 at 10:40 AM..
# 2  
Old 10-24-2019
Hi, try;
Code:
awk '/s_ohs_instance_loc/{print $2}' RS=\< FS=\> "$CONTEXT_FILE"

Last edited by Scrutinizer; 10-24-2019 at 12:48 PM..
# 3  
Old 10-24-2019
Here is one as well.
Code:
awk '/s_ohs_instance_loc/ && match($0,/>.*</) { print substr($0,RSTART+1,RLENGTH-2) } '

Regards
Peasant.
# 4  
Old 10-24-2019
Thanks to all.
# 5  
Old 10-24-2019
Quote:
Originally Posted by Peasant
Here is one as well.
Code:
awk '/s_ohs_instance_loc/ && match($0,/>.*</) { print substr($0,RSTART+1,RLENGTH-2) } '

[..]
One thing to note is that this will work as long as there are no other tags on the line where the match occurs..
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