Urgent.!!! Multiple if within while loop ksh


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# 1  
Urgent.!!! Multiple if within while loop ksh

Hi All,

I'm trying to write while loop with multiple if conditions. Each and every if condition with different variables. whenever one if condition fails i have remove the file
from filename and have to pick another file and loop should exit until the last file found in filename. Please help how to write a ksh shell script for that. Below i have given code what i tried

Thanks in advance.!!!

Code:
example:
#### here filename contain XXXX_YYYY_ZZZZ_DDD.txt as example
while read filename
#splitting a file without extension
full_filename=$filename
noextension=${full_filename%.*}
extension="${full_filename##*.}"

####assigning a patterns to different variable

echo "$noextension"|awk -F'_' '{ print NF-1 }' > countpattern

##### First fi######
if [ "$countpattern" -eq 5 ] ; then
A=$(echo $noextension|cut -d'_' -f1)
B=$(echo $noextension|cut -d'_' -f2)
C=$(echo $noextension|cut -d'_' -f3)
D=$(echo $noextension|cut -d'_' -f4)
E=$(echo $noextension|cut -d'_' -f5)
fi

####Second If########
if [ ! $extension=txt-a $A=HELP] || [ ! $extension=csv -a ! A =HELP ]
then
UPDATE TABLE ########################
rm full_filename
fi

####third if#####
if [ ! $C = "WE" ]
then
UPDATE TABLE ########################
rm full_filename
fi

# 2  
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# 3  
One way to break a huge logic statement like that into several smaller ones is:

Code:
while read filename
do
        REMOVE=0

        if [ ! condition1 ]
        then
                REMOVE=1
        fi


        if [ ! condition2 ]
        then
                REMOVE=1
        fi


        if [ ! condition3 ]
        then
                REMOVE=1
        fi

        if [ "$REMOVE" -eq 1 ]
        then
                remove_filename
        fi
done

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