How to search for a word in column header that fully matches the word not partially in awk?


 
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# 1  
Old 08-01-2019
How to search for a word in column header that fully matches the word not partially in awk?

I have a multicolumn text file with header in the first row like this

Quote:
Name xy_fill zxy_fill tz_fill
Fox 0 5 55
Snake 1 6 14
wolf 8 1 2
The headers are stored in an array called
Quote:
hdr
. which contains
Quote:
xy_fill tz_fill
I want to search for each elements of this
Quote:
hdr
array from that multicolumn text file. And I am using this awk approach

Code:
for ii in ${hdr[@]}
do

gawk -vcol="$ii" -F $'\t' ' 
$0 ~ col{
for(s=1;s<=NF;s++){ 
heading=$s 
colhdr[s]=heading
if(index(heading, col))wanted[s]=1
}
}
'

done

But this gives me both
Quote:
xy_fill
and
Quote:
zxy_fill
columns while searching for
Quote:
xy_fill
. How can I only read
Quote:
xy_fill
column?
For example if I search
Quote:
xy_fill
it should return column number 1 but my script is returning 1 and 2, which is wrong.

Last edited by Atta; 08-01-2019 at 05:07 AM..
# 2  
Old 08-01-2019
Not sure where to begin... - OK, let's try:


You're missing the multicolumn text file as an input to awk, so it doesn't know what to operate on.
Your awk code doesn't have a print statement, so nothing will be printed. So your result of 1 or 2 is a bit surprising. If it printed something, then the (desired) result for the given contents of hdr array should be 2 and 4, for the two elements as indicated.
Your pattern check $0 ~ col is quite unspecific, it will trigger on any occurrence of the pattern also later in the file - you may want to confine the action to the first line only.
It's not clear what the heading, colhdr, and wanted variables / arrays are meant for, as they aren't used anywhere.
You want a "word in column header that fully matches the word not partially", so why use the index function in lieu of an equals operator?


How far wqould this get you:
Code:
for ii in ${hdr[@]}
  do    awk -vcol="$ii" ' 
        NR == 1 {for (s=1; s<=NF; s++)  if ($s == col) print s
                }
        ' file
  done
2
4

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