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Print number of lines for files in directory, also print number of unique lines


 
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Top Forums UNIX for Beginners Questions & Answers Print number of lines for files in directory, also print number of unique lines
# 1  
Print number of lines for files in directory, also print number of unique lines

I have a directory of files, I can show the number of lines in each file and order them from lowest to highest with:

Code:
wc -l *|sort

15263 Image.txt
16401 reference.txt
40459 richtexteditor.txt

How can I also print the number of unique lines in each file?

Code:
15263 1401 Image.txt
16401 15999 reference.txt
40459 35670 richtexteditor.txt

If this is possible, how could I also sort it by unique vs overall count?
Moderator's Comments:
Mod Comment Please use CODE tags (not QUOTE tags) when displaying sample input, output, and code.

Last edited by Don Cragun; 07-11-2019 at 02:42 PM..
# 2  
how about this:
Code:
#!/bin/ksh

wc -l * | sed '$d' | sort | while read lines file junk
do
   echo $lines $(sort < $file | uniq -u |wc -l) $file
done

This User Gave Thanks to vgersh99 For This Post:
# 3  
Code:
awk '{u[$0]; l++} ENDFILE {print length(u), l, FILENAME; delete u; l=0}' * | sort -k1,1n

These 2 Users Gave Thanks to nezabudka For This Post:
# 4  
Quote:
Originally Posted by nezabudka
Code:
awk '{u[$0]; l++} ENDFILE {print length(u), l, FILENAME; delete u; l=0}' * | sort -k1,1n

this is gawk specific AND it does not count the unique lines correctly.
How about another version:
Code:
gawk '{l[$0]++} ENDFILE {for (i in l) {if (l[i]==1) u++;t+=l[i]} print t, u, FILENAME; delete l; u=t=0}' *

Test files:
file1:
Code:
1
2
3
3
4
1

file2:
Code:
1
2
3
3
4
1
5

These 2 Users Gave Thanks to vgersh99 For This Post:
# 5  
Please always tell us what shell and operating system you're using when you start a new thread. Don't assume that everyone who wants to help you has read all of your previous threads.
Code:
#!/bin/bash
tmpf="/tmp/$$.result"

trap 'rm -f "$tmpf"' EXIT

awk '
function dump() {
	print linecount, distinct, lastfile
	linecount = distinct = 0
	split("", lines)
}

FILENAME != lastfile {
	if(lastfile)
		dump()
	lastfile = FILENAME
}

{	linecount++
	if(lines[$0]++ == 0)
		distinct++
}

END {	dump()
}' * > "$tmpf"

echo 'Sorted by increaasing number of lines in files:'
sort -n "$tmpf"

echo 'Sorted by increaasing number of distinct lines in files:'
sort -k2,2n "$tmpf"

Note that this should work with any version of awk (but on Solaris systems, you'll need to use nawk or /usr/xpg4/bin/awk).

Last edited by Don Cragun; 07-11-2019 at 03:57 PM.. Reason: Improve efficiency of awk script. Add note.
This User Gave Thanks to Don Cragun For This Post:
# 6  
Suggestion with regular awk:

Code:
awk '
FNR==1 {
  filenr++
  Name[filenr]=FILENAME
}

!Seen[filenr,$0]++ {
  Uniq[filenr]++
} 

{
  Total[filenr]++
} 

END {
  for(i in Name)
    print Total[i], Uniq[i], Name[i]
}
' file* | sort -nk1,1 -nk2,2 -k3,3


Last edited by Scrutinizer; 07-11-2019 at 06:15 PM..
This User Gave Thanks to Scrutinizer For This Post:
# 7  
Quote:
Originally Posted by vgersh99
how about this:
Code:
#!/bin/ksh

wc -l * | sed '$d' | sort | while read lines file junk
do
   echo $lines $(sort < $file | uniq -u |wc -l) $file
done

The following variant correctly handles filenames with special characters:
Code:
for f in *; do printf "%s/%s lines are unique in file %s\n" $(sort "$f" | uniq -u | wc -l) $(wc -l < "$f") "$f"; done

Post #3 has another perception of "unique":
Code:
for f in *; do printf "%s/%s unique lines in file %s\n" $(sort  -u "$f" | wc -l) $(wc -l < "$f") "$f"; done

Didn't see the "sort" requirement. Left as an exercise.

Last edited by MadeInGermany; 07-11-2019 at 03:51 PM..
These 2 Users Gave Thanks to MadeInGermany For This Post:

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