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Execution problem with Cron

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Top Forums UNIX for Beginners Questions & Answers Execution problem with Cron
# 1  
Old 06-10-2019
Execution problem with Cron
Hi,
I'm unable to understand why the grep command in cronjob works intermittently

Expected output:
Grep command to look for a particular string with today's date and exit from infinite while loop else it must sleep for 5 mins

I'm using the following statement in my shell script, the variable $logString is empty even when the pattern exists in the log
Code:
while [ -z "$logString" ]
                do
                        echo "Sleep for 5 mins" >> $LOG
                        sleep 300
                        # logString=$(/usr/bin/perl -ne '/STATUS\s+\['"$month"'\/'"$day"'\s+(05|06).*\]\:\s+main\:\s+Active\s+region.*/ && print' << logname>>)
                        logString=$(grep "$(/usr/bin/date +"\%m/\%d")" /ilx/log/exrMngr.log | /usr/bin/grep ".*0[56]\:[0-9]\{2\}\:[0-9]\{2\}" | /usr/bin/grep 'Active region has been')
                        echo "String is: $logString" >> $LOG
                done

while it was successful in yesterday's cron run

Sleep for 5 mins
String is: STATUS [06/09 05:04:57]: main: Active region has been changed from: 0 to: 1

it failed today

Sleep for 5 mins
String is:

Moderator's Comments:
Mod Comment Please use code tags
Last edited by jim mcnamara; 06-10-2019 at 08:40 AM..
# 2  
Old 06-10-2019
Three things we need to help:
Code:
1 What UNIX?
2. What shell?
3. a sample of the log file that you know has the pattern.  A few lines are great.

Otherwise we are just guessing what is going on. Thanks.
This User Gave Thanks to jim mcnamara For This Post:
RavinderSingh13
# 3  
Old 06-10-2019
1 What UNIX?
- SunOS 11.4.5
2. What shell? -
- /bin/sh
3. a sample of the log file that you know has the pattern. A few lines are great.
Code:
             - STATUS [06/10 05:05:01]: Total counts of security records: 8982673.
               STATUS [06/10 05:05:02]: main: Active region has been changed from: 1 to: 0
               STATUS [06/10 05:06:02]: elapsed time: 60; vait_time: 1800

Cronjob starts at 5, ideally it should have exit at 05:05:02 when it finds the matching string


Snap from the cronjob log
Code:
============ Started at Sun Jun  9 05:00:00 EDT 2019 ==========
Put to maintenance
Sleep for 5 mins
String is: STATUS [06/09 05:04:57]: main: Active region has been changed from: 0 to: 1
Flush_cache.sh Completed
Taking the process out of maintenance

Last edited by vbe; 06-13-2019 at 06:53 AM..
# 4  
Old 06-12-2019
Any suggestions from anyone?
# 5  
Old 06-12-2019
Well, I can't see an error / failure. No "intermittend" behaviour. Data is from 10. June, and log (which seems to have worked) from 9. June. They can't possibly match.
# 6  
Old 06-27-2019
Hey RudiC
thanks for your response

I have managed to fix this issue, now its working consistently
There was no escape sequence needed for %m and %d

Now after fixing the line reads like this
Code:
logString=$(/usr/bin/grep "$(/usr/bin/date +"%m/%d")"  <log name> | /usr/bin/grep ".*0[56]\:[0-9]\{2\}\:[0-9]\{2\}" | /usr/bin/grep 'Active region has been')

# 7  
Old 06-27-2019
Why three greps? Why not
Code:
logString=$(/usr/bin/grep  "$(/usr/bin/date +"%m/%d") 0[56]\(:[0-9]\{2\}\)\{2\}.*Active region has been"  <log name>)
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