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How do I extract specific column in multiple csv files?

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# 1  
Old 06-06-2019
How do I extract specific column in multiple csv files?

Name,Threshold,Curr Samples,Curr Error%,Curr ART

Name,Threshold,Curr Samples,Curr Error%,Curr ART

Name,Threshold,Curr Samples,Curr Error%,Curr ART

similarly i have 21 csv files.i need to extract specific coloumn from all csv files and print in to a csv file.

if i mention Curr ART
example output:
Name,Curr ART,Curr ART,Curr ART,

can anyone help me on this..!
# 2  
Old 06-06-2019
awk -F, '
NR == 1         {for (i=1; i<=NF; i++) if ($i == SRCH) COL=i
                 HD = $1
FNR == 1        {FCNT++
                 HD = HD OFS SRCH
! EX[$1]++      {NM[++ROWCNT] = $1
                {T[$1,FCNT] = $COL
END             {print HD
                 for (i=1; i<=ROWCNT; i++)      {TMP = NM[i]
                                                 printf "%s", TMP
                                                 for (j=1; j<=FCNT; j++) printf ",%s", T[TMP,j]?T[TMP,j]:"NA" 
                                                 printf RS
' SRCH="Curr ART" OFS=, file[1-3]
Name,Curr ART,Curr ART,Curr ART

This User Gave Thanks to RudiC For This Post:
# 3  
Old 06-06-2019
Thanks its working for three filesSmilie ..need to check for my 24 files..i will check it and let u know..!
# 4  
Old 07-01-2019
Hi Rudic ..
i have 24 files and i have tried giving

' SRCH="Curr ART" OFS=, file[1-24]

it is not working then
it is working for only [1-9]
can u help me for 24 files??

i tried like complete command like file1 file2 file3........file24
the it worked

' SRCH="Curr ART" OFS=, file1 file2 file3 file4............file24

Last edited by Raghuram717; 07-01-2019 at 05:24 AM..
# 5  
Old 07-01-2019
In shell "pattern matching",
[...] Matches any one of the enclosed characters. A pair of characters separated by a hyphen denotes a range expression; any character that falls between those two characters, inclusive, using the current locale's collating sequence and character set, is matched.
(cf man bash). So, [1-24] matches 1, 2, and 4. For your case, you might want to try "brace expansion" (cf man bash):
echo file{1..24}
file1 file2 file3 file4 file5 file6 file7 file8 file9 file10 ... file23 file24

so, in lieu of explicitly listing each and every file name, have the shell do it for you.
This User Gave Thanks to RudiC For This Post:
# 6  
Old 07-01-2019
And, BTW, you might want to consider combining the solutions in this thread with the ones in your other thread?
This User Gave Thanks to RudiC For This Post:
# 7  
Old 07-04-2019
Just using standard shell features, one could also try:
' SRCH="Curr ART" OFS=, file[1-9] file1[0-9] file2[0-4]

or, assuming that there aren't any other filexx files where xx are decimal digits:
' SRCH="Curr ART" OFS=, file[1-9] file[12][0-9]

or, if there aren't any other files with names starting with file:
' SRCH="Curr ART" OFS=, file? file??


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