Versioning up a file with initials?


 
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# 1  
Old 05-17-2019
Versioning up a file with initials?

I have this code that works great ...

Code:
#!/bin/sh

for file in "$@"
do
        ext=${file##*.}
        base=${file%.*}
        num=${base##*v}
        zeroes=${num%%[!0]*}
        num=${num#$zeroes}      #remove leading zeros, or it uses octal
        num=$((num+1))
        base=${base%v*}
        new=$(printf '%sv%04d.%s' "$base" "$num" "$ext")
        cp -nv "$file" "$new"
done

Now I need it to work with a file that has two characters after the version number.
098_FGT_550_comp_v002gp.nk

I've tried just about everything I know to get this to work but it seems the characters get picked up as part of the number.

Any help is appreciated.

Thank you.
# 2  
Old 05-17-2019
You could try adding these intermediate steps after num=${base##*v} to remove trailing characters after the last digit (what you call "initials"):
Code:
initials=${num##*[0-9]}
num=${num%"${initials}"}


Last edited by Scrutinizer; 05-17-2019 at 11:31 PM..
# 3  
Old 05-18-2019
That works but I lose the "initials."
The file produced is 098_FGT_550_comp_v0003.nk

Once I get this working, several different people will be using it, so I need it to restore the initials.
# 4  
Old 05-18-2019
Not sure where the problem is:
Code:
printf '%sv%04d%s.%s' "$base" "$num" "$initials" "$ext"
 098_FGT_550_comp_v0002gp.nk

Your three digit version number has become four digit with your printf format.


Or, why not (provided you have a recent bash or ksh)



Code:
IFS="v."
ARR=( $file )
echo cp "$file" "$(printf '%sv%04d%s.%s\n' "${ARR[0]}" "$((10#${ARR[1]%%[^0-9]*} + 1))" "${ARR[1]##*[0-9]}" ${ARR[-1]})"
cp 098_FGT_550_comp_v002gp.nk 098_FGT_550_comp_v0003gp.nk


Last edited by RudiC; 05-18-2019 at 05:57 AM..
# 5  
Old 05-18-2019
Quote:
Originally Posted by scribling
That works but I lose the "initials."
The file produced is 098_FGT_550_comp_v0003.nk

Once I get this working, several different people will be using it, so I need it to restore the initials.
With the intermediate steps I suggested, the "initials" are saved in the initials variable, so you can use them wherever you please.
So try:
Code:
new=$(printf '%sv%04d%s.%s' "$base" "$num" "$initials" "$ext")

If they need to go somewhere else, then please specify the end result.

Last edited by Scrutinizer; 05-18-2019 at 06:59 AM..
# 6  
Old 05-18-2019
That works great!
Thank you.

It seems to easy now that I see it done correctly.
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