How to display processes which have been running for more than a X hours?


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# 1  
How to display processes which have been running for more than a X hours?

Hi,

Is it possible to display processes which have been running for more than a 5hrs using a variation of the ps -ef command?

Regards,

Manny
# 2  
The ps command output varies per platform, so could you specify what OS you are using?

On Linux you could try:
Code:
ps -eo pid,etimes | awk '$2/3600>=5{print $1}'

# 3  
Code:
ps -eo pid,etime

and the "no header" variant
Code:
ps -e -o pid= -o etime=

are quite portable (Posix standard).
The usual output format for times is D-HH:MM:SS
where the D- (=days) prefix is only printed if D > 0
This User Gave Thanks to MadeInGermany For This Post:
# 4  
Sorry, i should have said, this command needs to run on a unix (solaris) operating system.

Thanks.
# 5  
Quote:
Originally Posted by mantas44
Sorry, i should have said, this command needs to run on a unix (solaris) operating system.

Thanks.
So, since you're using a Solaris/SunOS system, instead of using:
Code:
ps -eo pid,etime

and the "no header" variant
Code:
ps -e -o pid= -o etime=

use:
Code:
/usr/xpg4/bin/ps -eo pid,etime

and the "no header" variant
Code:
/usr/xpg4/bin/ps -e -o pid= -o etime=

# 6  
Have to add that even the HH: is usually omitted if HH is zero.
A suitable postprocessing with awk:
Code:
ps -e -o pid= -o etime= | /usr/xpg4/bin/awk '{ n=split($NF, A, /[-:]/); seconds=(A[n]+60*(A[n-1]+60*(A[n-2]+24*A[n-3]))) } (seconds > 5*3600) { print $1 }'

The { print $1 } prints only the pids.
Another example with two more columns and printing everything:
Code:
ps -e -o pid= -o user= -o args= -o etime= | /usr/xpg4/bin/awk '{ n=split($NF, A,  /[-:]/); seconds=(A[n]+60*(A[n-1]+60*(A[n-2]+24*A[n-3]))) } (seconds > 5*3600)'

BTW Sun made the /usr/bin/ps Posix compliant; there is no /usr/xpg4/bin/ps. But df, find, awk, and >60 more Posix compliant commands live in /usr/xpg4/bin/

Last edited by MadeInGermany; 03-07-2019 at 11:18 AM.. Reason: $NF and another example.
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