If condition on awk

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# 1  
Old 02-08-2019
If condition on awk

Hi All,

Would you guys help me?

I have a file that consists of several unstructured fields. in this file I will take the code field and count_berry field.
but the position of the count_berry field is always changing.the column for code is always structured, which is found in column 6
I have found the count_berry field to be in a definite column, that is in columns 10, 12 (count_berry, 100) then in column 14.16 (count_berry, 10) then in column 24.26 (count_berry, 200).
so I can create a script to retrieve the columns and values ​​by using awk like this:
cat file |awk '$10 == "\"count_berry\"" {print $6 "," $12 };$14 == "\"count_berry\"" {print $6 "," $16};$24 == "\"count_berry\"" {print $6 "," $26}'

the problem is, how do I get an unknown count_berry column? can anyone help me make the if condition code on awk?

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Mod Comment Mod's comment: Please use formal/plain English language in forums posts as advised previously too.

Last edited by RavinderSingh13; 02-08-2019 at 12:53 AM..
# 2  
Old 02-08-2019
Try so
awk '{ for ( i=1; i <= NF; i++ ) if ( $i ~ var ) print $6,$i }' var=count_berry file

This User Gave Thanks to nezabudka For This Post:
# 3  
Old 02-08-2019
In this case it is $(i+2)
awk '{ for ( i=1; i <= NF; i++ ) if ( $i==var ) print $6,$(i+2) }' var='"count_berry"' file

These 2 Users Gave Thanks to MadeInGermany For This Post:
# 4  
Old 02-08-2019
Originally Posted by MadeInGermany
In this case it is $(i+2)
awk '{ for ( i=1; i <= NF; i++ ) if ( $i==var ) print $6,$(i+2) }' var='"count_berry"' file

Thankyou so much !!
# 5  
Old 02-08-2019
How about

awk '{match ($0, /count_berry/); split (substr ($0, RSTART), T); print $6, T[3]}' file

These 2 Users Gave Thanks to RudiC For This Post:
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