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Replace integer string in a variable based on month?

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# 8  
Old 11-12-2018
Rudi -

I'm literally using your code you gave me. Version in first post.

Linux Version = Linux 2.6.39-400.128.17.el5uek x86_64

Code:
#!/bin/bash

GLP() { 
    IFS=";" T=($(locale abmon))
    IFS=- read EM EY <<< $(date -d "$(date +%Y-%m-1) -1 month" +%-m-%Y)
    IFS=- read SM SY <<< $(date -d "$(date +%Y-%m-1) -$(($2+0?$2:EM)) month" +%-m-%Y)
    _ENDPOV=${T[EM-1]}-${EY:4-$1}
    _STARTPOV=${T[SM-1]}-${SY:4-$1}
}

GLP "2" "2"

echo $_ENDPOV
echo $_STARTPOV

# 9  
Old 11-12-2018
Run with -x (xtrace) option set. What's your shell version?
# 10  
Old 11-12-2018
Hi Rudi -

It's as follows:

Quote:
GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.
Thanks!

------ Post updated at 11:49 AM ------

Interestingly enough, it works fine on this version of shell:

Quote:
GNU bash, version 4.2.46(2)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2011 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
Any thoughts?
# 11  
Old 11-12-2018
Yes - 3.2.25(1) is too old.
# 12  
Old 11-12-2018
:-( Thank you.
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