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Linux find jpg and sort by date

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# 1  
Old 02-06-2018
Linux find jpg and sort by date
I want to find all jpg files and then sort them by modification date. This is where I started.

Code:
find . -type f -name "*.jpg"

I tried to pipe a sort in there but that did not seem to work. Do I need to use xargs?
# 2  
Old 02-06-2018
As you know well, all threads in this forum should start with:
What shell are you using?
What operating system are you using?

The find utility is great for finding files that were last modified in specified ranges of dates relative to the current time or to a single given other file. It is not generally good for comparing dates of selected files. If you want a list of files in last modified time order and the files are all in one directory, the simple way is with ls:
Code:
ls -t *.jpg

to get a list of files with the most recently modified file first, or:
Code:
ls -rt *.jpg

to get a list of files with the most recently modified file last.

So, for this thread, are these files all located in the current directory? Or, are they located in the current directory and various subdirectories under it? If in subdirectories, are they all at the same level or are they present in directories with varying levels under the current directory? And, how many files are we talking about here?
# 3  
Old 02-07-2018
You allude you're using linux in the thread header; so your find version might provide the -ls and / or -printf option to yield the files' modification times for sorting.
# 4  
Old 02-07-2018
Quote:
Originally Posted by Don Cragun
As you know well, all threads in this forum should start with:
What shell are you using?
What operating system are you using?

The find utility is great for finding files that were last modified in specified ranges of dates relative to the current time or to a single given other file. It is not generally good for comparing dates of selected files. If you want a list of files in last modified time order and the files are all in one directory, the simple way is with ls:
Code:
ls -t *.jpg

to get a list of files with the most recently modified file first, or:
Code:
ls -rt *.jpg

to get a list of files with the most recently modified file last.

So, for this thread, are these files all located in the current directory? Or, are they located in the current directory and various subdirectories under it? If in subdirectories, are they all at the same level or are they present in directories with varying levels under the current directory? And, how many files are we talking about here?
Fedora
Bash

I thought all Linux/Unix distro has the find command. Is that correct?

I want to search my entire computer. I was trying to keep things simple until I figured out the correct command thats why I used "." instead of "/".
# 5  
Old 02-07-2018
Quote:
Originally Posted by cokedude
Fedora
Bash

I thought all Linux/Unix distro has the find command. Is that correct?

I want to search my entire computer. I was trying to keep things simple until I figured out the correct command thats why I used "." instead of "/".
All UNIX, Linux, and BSD systems come with a find utility. But some versions of find have additional primaries that are not specified by the standards and are not available on all systems (such as those mentioned by RudiC in post #3).

On Linux systems, you could use one of those extensions to have find print a timestamp and the pathname of the file and sort the output produced by find on the timestamp field to get what you want.

On other systems, you might be able to use a -exec command {} + primary to get similar results. The command you would need to execute to get that data would vary from system to system.
# 6  
Old 02-07-2018
I think that -printf is the way to go. How do you want your date formatted for sorting?

I try to avoid saying this, but because there are lots, have a look at the man page for find to see the -printf options, such as %T@ which should give you epoch time and %p for the file name, similar to this:-
Code:
$ find . -printf '%T@ %p\n' |sort -n
1468598452.8015045550 ./unix.267273
1469099367.4486924810 ./file
1469100780.3309757180 ./input_file
1469805378.8660758160 ./267560.awk
1472213536.2868345460 ./count_binary_ones_length
1473928430.3601179200 ./in_file
1473928450.3837659940 ./exlcude
1486047098.9868200550 ./nic-thread-starter
1486111917.7097520520 ./270776/third.sh
1486111950.7201366120 ./270776/first.sh
1486111961.6289332250 ./270776/second.sh
1486112897.4140065720 ./270776
1486468608.9861686310 ./grep_spaces_test
1497523515.7209519850 ./272988/query.txt
1497524690.3125581780 ./272988/list.txt
1497524690.6745528860 ./272988
1503566805.5129076610 ./273839
1506421269.4751714080 ./filename
1507629323.3051139490 ./code
1508408914.3578552190 ./long.xml
1509709907.2805843090 ./list1
1509709920.6723868540 ./list2
1510826780.6306387540 ./runasroot.sh
1515412336.1583844750 ./as7951.in
1515414517.2548585810 ./dc.bash
1515499084.4714352250 ./status.html
1515504964.6037726290 ./xx00
1517325854.0620988160 ./276758.in
1517325854.1210979050 .


Does that help? Maybe you need another format, but you then have to consider sort options. Of course, it depends on which OS and version you are running for the various flags for find.


Robin
# 7  
Old 02-07-2018
Another way to go might be the stat command, of which various versions exist across OS'. Linux version:
Code:
stat -c"%y %n" fi*
2018-02-02 14:22:22.143035263 +0100 file
2018-02-02 14:13:40.000000000 +0100 file~
2018-02-06 18:51:45.850714122 +0100 file1
2018-02-06 18:48:31.000000000 +0100 file1~

or
Code:
stat -c"%Y %n" fi*
1517577742 file
1517577220 file~
1517939505 file1
1517939311 file1~
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